it will be an error as for as i know... since s1 is not a pointer variabl

#include<stdio.h>
main()
{
char s1[]="Ramco";
char s2[]="Systems";
s1=s2;
printf("%s",s1);
}
Find the output

Question Posted / vignesh1988i

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Answer Posted / vignesh1988i

it will be an error as for as i know... since s1 is not a
pointer variable... but however array are implict
pointers.... here we cant assign the base address to
another arry which is capable of holding oly values not
addressses...............

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