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There are 9 coins. Out of which one is odd one i.e weight
is less or more. How many iterations of weighing are
required to find odd coin?
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Answer Posted / vikram
ans: 3 iterations
divide coins in batches of 3
do 2 iterations of the batches u would know which is
defective batch and also wheather its lighter r heavier.
in another iteration of defective batch u would find
defective coin.
| Is This Answer Correct ? | 15 Yes | 27 No |
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