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#include <stdio.h>
#define sqr(x) (x*x)
int main()
{
int x=2;
printf("value of x=%d",sqr(x+1));
}
What is the value of x?
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Answer Posted / gg
Ans : 5
I agree with Divakar ans & similar answers.
sqr(x+1)=x+1*x+1=2+1*2+1=5, but not 2*2+1
| Is This Answer Correct ? | 17 Yes | 0 No |
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