If we have an array of Interger values, find out a sub array
which has a maximum value of the array and start and end
positions of the array..The sub array must be contiguious.
Take the start add to be 4000.
For Ex if we have an array arr[] =
{-1,-2,-5,9,4,3,-6,8,7,6,5,-3}
here the sub array of max would be
{8,7,6,5} coz the sum of max contiguous array is 8+7+6+5 =
26.The start and end position is 4014(8) and 4020(5).
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Answer Posted / manoj
Another approach
# include<stdio.h>
struct index {
int sum;
int start;
int end;
};
int main()
{
struct index sumidx[30],*tmp;
int i,j,z =0,len;
int a[30];
printf("\n Enter the Number of elements to be entered
in the array :\n");
scanf("%d",&len);
printf("\n Enter the array Values : \n");
for(i=0;i<len;i++)
scanf("%d",&a[i]);
for(i = 0;i <len - 1;i++)
{
sumidx[z].sum = a[i];
sumidx[z].start = i;
sumidx[z].end = i;
for(j=i+1;j<len;j++)
if(sumidx[z].sum < (sumidx[z].sum + a[j]))
{
sumidx[z].sum = sumidx[z].sum + a[j];
sumidx[z].start = i;
sumidx[z].end = j;
}
else
break;
z++;
}
tmp = sumidx;
for(i = 0;i<z;i++)
{
if(sumidx[i].start != sumidx[i].end)
if(tmp->sum < sumidx[i].sum)
tmp = sumidx+i;
}
printf("\n sum = %d start = %d end
%d\n",tmp->sum,tmp->start,tmp->end);
return 0;
}
| Is This Answer Correct ? | 2 Yes | 2 No |
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