What is the melting temperature of the cng long tube fusible plug? And can I use lead solder Sn97Cu3 (Melting temp S/L 227-309 °C) Materials of tube : AISI 4130 Alloy steel
1561Question 51 - A batch reactor is designed for the system of the irreversible, elementary liquid-phase hydration of butylene oxide that produces butylene glycol. At the reaction temperature T = 323 K, the reaction rate constant is k = 0.00083 L / (mol - min). The initial concentration of butylene oxide is 0.25 mol / L = Ca. The reaction is conducted using water as the solvent, so that water is in large excess. (a) Let the molecular weight of water is 18 g / mol and the mass of 1 kg in 1 L of water, calculate the molar density of water, Cb in the unit of mol / L. (b) Determine the final conversion, X of butylene oxide in the batch reactor after t = 45 min of reaction time. Use the formula X = 1 - 1 / exp [ kt (Cb) ] derived from material balance. (c) Find the equation of t as a function of X.
1 2946Question 62 – The names of the flow streams could be represented by : H1 for first hot stream, H2 for second hot stream, C1 for first cold stream, C2 for second cold stream. Data of supply temperature Ts in degree Celsius : 150 for H1, 170 for H2, 30 for C1, 30 for C2. Data of target temperature Tt in degree Celsius : 50 for H1, 169 for H2, 150 for C1, 40 for C2. Data of heat capacity Cp in kW / degree Celsius : 3 for H1, 360 for H2, 3 for C1, 30 for C2. (a) Find the enthalpy changes, dH for all streams of flow H1, H2, C1 and C2 in the unit of kW. Take note of the formula dH = (Cp) (Tt - Ts). (b) Match the hot streams H1 and H2 with the suitable cold streams C1 and C2 to achieve the maximum energy efficiency.
1 2152In which state sulphur exists at 40 degrees temperature and 40 atmospheric pressure in natural gas having sulphur composition 0.1 ppm?
1608Question 72 - (a) According to United States Department of Agriculture (USDA) (http://ndb.nal.usda.gov/ndb/search/list, accessed 12 August 2016), 100 g of potatoes generate 77 kcal of energy. For raw tomatoes, 111 g have 18 kcal of energy. Question : How much energy will one gain if 150 g of heated potatoes are eaten with 200 g of raw tomatoes? (b) If 1 Calorie = 1 food Calorie = 1 kilocalorie and 1000 calories = 1 food Calorie, then how many Calories are there in 9600 calories? (c) According to a food package of potato chips, 210 Calories are produced per serving size of 34 g. In actual experiment of food calorimetry lab, 1.75 g of potato chips, when burnt, will produce 9.6 Calories. For each serving size of potato chip, find the difference of Calories between the actual experimental value and the value stated on the food package. (d) The specific heat of water is c = 1 cal / (g.K) where cal is calory, g is gram and K is Kelvin. Then what is the temperature rise of water, in degree Celsius, when 150 g of water is heated by 9600 calories of burning food?
1 2746Question 73 - (a) A dryer reduces the moisture content of 100 kg of a potato product from 80 % to 10 % moisture. Find the mass of the water removed in such drying process. (b) During the drying process, the air is cooled from 80°C to 71°C in passing through the dryer. If the latent heat of vaporization corresponding to a saturation temperature of 71°C is 2331 kJ / kg for water, find the heat energy required to evaporate the water only. (c) Assume potato enters at 24°C, which is also the ambient air temperature, and leaves at the same temperature as the exit air. The specific heat of potato is 3.43 kJ / (kg °C). Find the minimum heat energy required to raise the temperature of the potatoes. (d) 250 kg of steam at 70 kPa gauge is used to heat 49,800 cubic metre of air to 80°C, and the air is cooled to 71°C in passing through the dryer. If the latent heat of steam at 70 kPa gauge is 2283 kJ / kg, find the heat energy in steam. (e) Calculate the efficiency of the dryer based heat input and output, in drying air. Use the formula (Ti - To)/(Ti - Ta) where Ti is the inlet (high) air temperature into the dryer, To is the outlet air temperature from the dryer, and Ta is the ambient air temperature.
1 5885i have a 4 Mva transformer 34.5 kv / 480-277 v and i used 2 parallel 3200 amp bus duct for the secondary feeder using 3 ply of bus bar ( 3/8" x 5" ) as a common where the flexible link terminated and 6300 amps breaker for the main, the lower bus duct reaches 70 degrees and the upper bus duct reaches 55 degrees when i used thermal scanner. why the temperature is not balance when the load reaches 3600 amps.
SCM,
1873Question 78 - Fact 1 : Dry air contains 20.95 % oxygen, 78.09 % nitrogen, 0.93 % argon, 0.039% carbon dioxide, and small amounts of other gases by volume. Fact 2 : Volume occupied is directly proportional to the number of moles for ideal gases at constant temperature and pressure. Fact 3 : 12.5 moles of pure oxygen is required to completely burn 1 mole of pure octane. Fact 4 : Air–fuel ratio (AFR) is the mass ratio of dry air to fuel present in a combustion process such as in an internal combustion engine or industrial furnace. Fact 5 : Molecular weight of oxygen gas is 31.998 g / mole and molecular weight of nitrogen gas is 28.014 g / mole. (a) Find the molar ratio of nitrogen and oxygen, or (moles of nitrogen) / (moles of oxygen) in dry air, by assuming ideal features of nitrogen and oxygen gases. (b) How many moles of nitrogen are available if dry air is used to completely burn the 1 mole pure octane? (c) Find the mass of fuel of 1 mole of octane with molecular weight of 114.232 g / mole. (d) Find the mass of dry air with 12.5 moles of pure oxygen by assuming only oxygen and nitrogen gases exist in the air. (e) Find the air-fuel ratio (AFR) when octane is used as fuel. (f) Find the fuel-air ratio (FAR) when octane is used as fuel.
1 2642CHEMICAL MATERIAL BALANCE - EXAMPLE 2.4 : A mixture consists of benzene (B), toluene (T) and xylene (X). At a temperature of 353 K, the data of vapor pressures : B : 754.12, T : 289.71, X : 91.19. Unit is mm Hg. The pressure P is 0.5 atm. The value of k for each substance is k = (vapor pressure) / P. (a) Calculate k for B, T and X. Let L / V = 0.65. (b) By using the equation V = F / [ (L / V) + 1 ], find the value of V when F = 100, then what is the value of L?
1 2346
How does Vbe and Ic change with temperature?
what are the microbes that grow if proper temperatures are not maintained during fermentation process?
At what temperature should fresh sweet potato leaves be stored and dried?
How the plants can survive in Tundra where temperature reaches -57oC?
I currently use 17-7 PH stainless which is hardened to condition CH after forming. raw matl is .1.75"X .12" X .008". Its main usage after hardening is silicon wafer retainer where it's contantly cycled up and down to putin and remove wafer after 40-60 sec process at 400C temp. At this high temperature this part seemed to deform after a a couple of hundred wafer which is what it was designed for in the first place. THere is a proposal to go to a different material to increase lifeline of this part. My question is..... can 321 SST be a plugin replacement. I know this has a higher temp rating but how about its forming characteristics, will it have spring properties, and wont become brittle after prolonged exposure to 400C.
Design a program which assigns values to the array temperature. The program should then display the array with appropriate column and row headings.
An ice-box is built of wood 1.75 cm thick, lined with cork 3 cm thick. If in the steady state the temperature of the inner surface of the cork is 0 ºC and that of the outer surface of wood is 12 ºC, what is the temperature of the wood-cork interface? The thermal conductivities of wood and cork are 0.2 W/m-K and 0.04 W/m-K respectively
What is the temperature PROFILE OF A FLUID W. R. T. Distance from a sphere to which it is IN CONTACT which is at constant temp.?
In which working principal temperature transmitter work.explain in detailed.
hii..i am doin a project called Forecaster..wat it does is it asks user to enter a zip code..then it establishes urlconnection with a weather website n fetches data n data is converted into graphical representation..but it doesnt show any output..i am not able it figure out the reason..can u plzzzz help me out..i am givin u code import java.io.*; import java.awt.*; import java.net.*; import java.awt.image.*; import java.awt.event.*; public class Forecast extends Frame { OkCancelDialog textDialog; BufferedImage image = null; public static void main(String[] args) { new Forecast(); } public Forecast() { String zip =""; File zipFile = new File("zip.txt"); String hiTemperature[] = new String[4]; String loTemperature[] = new String[4]; try { if(zipFile.exists()){ FileReader filereader = new FileReader("zip.txt"); BufferedReader bufferedreader = new BufferedReader(filereader); zip = bufferedreader.readLine(); } else { textDialog = new OkCancelDialog(this, "Enter your five-digit zip code", true); textDialog.setVisible(true); zip = textDialog.data.trim(); FileOutputStream fileoutputstream = new FileOutputStream("zip.txt"); fileoutputstream.write(zip.getBytes()); } int character; URL url = new URL ("http://www.srh.noaa.gov/zipcity.php?inputstring=" + zip); URLConnection urlconnection = url.openConnection(); InputStream in = urlconnection.getInputStream(); String input = ""; String hiSearch; String loSearch; String inchar; char[] cc = new char[1]; while ((character = in.read()) != -1) { char z = (char)character; cc[0] = z; inchar = new String(cc); input += inchar; } in.close(); if(input.indexOf("Hi ") >= 0){ hiSearch = "Hi "; } else{ hiSearch= "Hi: "; } int currentPosition = 0; for(int loopIndex = 0; loopIndex < 4; loopIndex++){ int location = input.indexOf(hiSearch, currentPosition); int end = input.indexOf("°", location); hiTemperature[loopIndex] = input.substring(location + hiSearch.length(), end); currentPosition = end + 1; } if(input.indexOf("Lo ") >= 0){ loSearch = "Lo "; } else{ loSearch= "Lo: "; } currentPosition = 0; for(int loopIndex = 0; loopIndex < 4; loopIndex++){ int location = input.indexOf(loSearch, currentPosition); int end = input.indexOf("°", location); loTemperature[loopIndex] = input.substring(location + loSearch.length(), end); currentPosition = end + 1; } boolean evening = false; if(input.indexOf(loSearch) < input.indexOf(hiSearch)){ evening = true; hiTemperature[3] = hiTemperature[2]; hiTemperature[2] = hiTemperature[1]; hiTemperature[1] = hiTemperature[0]; } image = new BufferedImage(225, 201, BufferedImage.TYPE_INT_RGB); Graphics2D g = image.createGraphics(); g.setColor(Color.white); g.fillRect(0, 0, 224, 201); g.setColor(Color.gray); for(int loopIndex = 0; loopIndex < 21; loopIndex++){ g.drawLine(25, loopIndex * 10, 224, loopIndex * 10); g.drawLine(loopIndex * 10 + 25, 0, loopIndex * 10 + 25, 199); } g.setColor(Color.blue); Font font = new Font("Courier", Font.PLAIN, 18); g.setFont(font); for(int loopIndex = 20; loopIndex < 200; loopIndex += 20){ g.drawString(String.valueOf(100 - loopIndex / 2), 0, loopIndex + 5); } g.setColor(Color.red); if(!evening){ g.drawOval(65 - 4, 200 - (Integer.parseInt( hiTemperature[0]) * 2) - 4, 8, 8); } g.drawOval(105 - 4, 200 - (Integer.parseInt( hiTemperature[1]) * 2) - 4, 8, 8); g.drawOval(145 - 4, 200 - (Integer.parseInt( hiTemperature[2]) * 2) - 4, 8, 8); g.drawOval(185 - 4, 200 - (Integer.parseInt( hiTemperature[3]) * 2) - 4, 8, 8); if(!evening){ g.drawLine(65, 200 - (Integer.parseInt( hiTemperature[0]) * 2), 105, 200 - (Integer.parseInt(hiTemperature[1]) * 2)); } g.drawLine(105, 200 - (Integer.parseInt(hiTemperature[1]) * 2), 145, 200 - (Integer.parseInt(hiTemperature[2]) * 2)); g.drawLine(145, 200 - (Integer.parseInt(hiTemperature[2]) * 2), 185, 200 - (Integer.parseInt(hiTemperature[3]) * 2)); g.setColor(Color.blue); g.drawOval(65 - 4, 200 - (Integer.parseInt( loTemperature[0]) * 2) - 4, 8, 8); g.drawOval(105 - 4, 200 - (Integer.parseInt( loTemperature[1]) * 2) - 4, 8, 8); g.drawOval(145 - 4, 200 - (Integer.parseInt( loTemperature[2]) * 2) - 4, 8, 8); g.drawOval(185 - 4, 200 - (Integer.parseInt( loTemperature[3]) * 2) - 4, 8, 8); g.drawLine(65, 200 - (Integer.parseInt(loTemperature[0]) * 2), 105, 200 - (Integer.parseInt(loTemperature[1]) * 2)); g.drawLine(105, 200 - (Integer.parseInt(loTemperature[1]) * 2), 145, 200 - (Integer.parseInt(loTemperature[2]) * 2)); g.drawLine(145, 200 - (Integer.parseInt(loTemperature[2]) * 2), 185, 200 - (Integer.parseInt(loTemperature[3]) * 2)); g.setColor(Color.white); g.fillRect(55, 160, 140, 30); g.setColor(Color.blue); g.drawRect(55, 160, 140, 30); font = new Font("Courier", Font.PLAIN, 12); g.setFont(font); g.drawString("Four-Day Forecast", 65, 172); font = new Font("Courier", Font.PLAIN, 9); g.setFont(font); g.drawString("Source: Nat. Weather Srvce.", 58, 185); setTitle("The Forecaster"); setResizable(false); setSize(250, 240); setVisible(true); this.addWindowListener(new WindowAdapter(){ public void windowClosing( WindowEvent e){ System.exit(0); } } ); } catch (Exception e) { System.out.println(e.getMessage()); } } public void paint(Graphics g) { if(image != null){ g.drawImage(image, 10, 30, this); } } } class OkCancelDialog extends Dialog implements ActionListener { Button ok, cancel; TextField text; public String data; OkCancelDialog(Frame hostFrame, String title, boolean dModal) { super(hostFrame, title, dModal); setSize(280, 100); setLayout(new FlowLayout()); text = new TextField(30); add(text); ok = new Button("OK"); add(ok); ok.addActionListener((ActionListener)this); cancel = new Button("Cancel"); add(cancel); cancel.addActionListener(this); data = new String(""); } public void actionPerformed(ActionEvent event) { if(event.getSource() == ok){ data = text.getText(); } else { data = ""; } setVisible(false); } }
IN 1000kva transformer where the oil and winding temperature sensors is connected
1600kva capacity Transformers how the bucholz relay,Oil temperature,winding,surge relay relays setting are to be done
What is critical pressure ?. What will happen if water is heated above critical pressure and temperature?. What importance it is having related to Boiler?. Upto what presrure natural circulation is possible in Boilers?.
For the requirement of a furnace of temperature range up to 1200 oC using silicon carbide rods, What is the required rate of transformer needed (please do it with all details)?
What is the maximum cylinder head temperature of a 1200 KW, 12 cylinders DG set