Answer / fhghg

#include<stdio.h>
int n_fact(int n);
void main()
{
int n,res=0;
printf("ENTER A NUMBER:-");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
res+=n_fact(n);
}
printf("%d",res);
}
int n_fact(n)
{
int result;
if(n=0)
result=1;
else
result=n*n_fact(n-1);
return(result);
}

Answer / vignesh1988i

#include<stdio.h>
#include<conio.h>
long factorial(int,long);
void main()
{
int i,m;
long sum=0,k=1;
clrscr();
printf("enter ur no. of terms :");
scanf("%d",&m);
i=1;
while(i<=m)
{
k=factorial(i,k);
sum+=k;
i++;
}
printf("the sum is : %ld",sum);
getch();
}
int factorial(int i,long k)
{
return (i*k);
}

hope this also correct...
thank u

Answer / yamuna

/* A.Yamuna III BSC CS L.R.G. College , Tirupur*/
#include<stdio.h>
#include<conio.h>
void main()
{
int a,n;
int sum=1;
int total=0;
clrscr();
printf("Enter the number :");
scanf("%d",&n);
for(a=1;a<=n;a++)
{
for(int i=1;i<=a;i++)
{
sum=sum*i;
}
total=total+sum;
sum=1;
}
printf("The factorial is :%d",total);
getch();
}

Answer / ashish

#include<stdio.h>
int n_fact(int n);
void main()
{
int n,res;
printf("ENTER A NUMBER:-");
scanf("%d",&n);
res=n_fact(n);
printf("%d",res);
}
int n_fact(n)
{
int result;
if(n=0)
result=1;
else
result=n*n_fact(n-1);
return(result);
}

main() {char a[10]={1,2,3,4,5,6};int x; for(x=0;x<4;x++){ b[x]=x+'a';} printf("%s",b);}

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