write a c program to print a given number as odd or even
without using loop statements,(no if ,while etc)
Answers were Sorted based on User's Feedback
#include<stdio.h>
#include<conio.h>
void main()
{
int m;
printf("0 - odd number \t 1 - even number\n");
printf("enter the number :");
scanf("%d",&m);
printf(" %d ",m&1);
getch();
}
thank u
| Is This Answer Correct ? | 43 Yes | 27 No |
Answer / avinash kumar
#include<stdio.h>
main()
{
int a;
clrscr();
printf("enter a number:");
scanf("%d",&a);
if(a%2=0)
printf("even");
else
printf("odd")
getch();
}
| Is This Answer Correct ? | 25 Yes | 22 No |
Answer / p.thirugnanavel
#include<stdio.h>
#include<conio.h>
void main()
{
int no,ch;
clrscr();
printf("enter the number :");
scanf("%d",&no);
ch=(no%2==0) ? (1) : (2);
switch(ch)
{
case 1:
printf("The number %d is even",no);
break;
case 2:
printf("The number %d is odd",no);
break;
}
getch();
}
| Is This Answer Correct ? | 7 Yes | 5 No |
Answer / dheerendra
logic
main()
{
int a;
(a%2==0)?printf("even"):printf("odd")
}
| Is This Answer Correct ? | 4 Yes | 4 No |
Answer / manojkumar
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
clrscr();
printf("enter the number :");
scanf("%d",&a);
b=a%2;
switch(b)
{
case 1:
printf("The number %d is even",no);
break;
case 2:
printf("The number %d is odd",no);
break;
}
getch();
}
| Is This Answer Correct ? | 3 Yes | 4 No |
Answer / bhabesh rai
#include<stdio.h>
main()
{
int n;
printf("Enter an integer:\n");
scanf("%d", &n);
switch((n%2 == 0) ? (1) : (2))
{
case 1:
printf("EVEN\n", n);
break;
case 2:
printf("ODD\n", n);
break;
}
}
| Is This Answer Correct ? | 2 Yes | 3 No |
sorry , just change printf() as.... printf("0 - even number \t 1 - odd number \n ");
thank u
| Is This Answer Correct ? | 12 Yes | 19 No |
Answer / dr:rahul
#include<stdio.h>
#include<conio.h>
void main()
{
int rahul;
printf("0 - odd number \t 1 - even number\n");
printf("enter the number :");
scanf("%d",&rahul);
printf(" %d ",rahul&1);
getch();
}
| Is This Answer Correct ? | 4 Yes | 14 No |
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