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Program to find greatest prime number in n numbers?
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Answer / rajani nagandla
Sorry. initialize i=2 directly as 2 is the first prime
number.. no need of checking for 1.
| Is This Answer Correct ? | 10 Yes | 3 No |
Answer / manikandan
<----------------- Import appropriate pkgs ------------->
public class Mainmain
{
public static void main(String[] args) throws IOException
{
BufferedReader br= new BufferedReader(new
InputStreamReader(System.in));
System.out.println("Enter the no of nos");
int n=Integer.parseInt(br.readLine());
int[] a= new int[n];
System.out.println("Enter the nos");
for(int i=0;i<n;i++)
{
a[i]=Integer.parseInt(br.readLine());
}
Arrays.sort(a);
LOOP: for(int i=n-1;i>=0;i--)
{
int b=2;
boolean c=true;
while(b<a[i])
{
if((a[i]%b)==0)
{
c=false;
continue LOOP;
}
b++;
}
if(c)
{
System.out.println("The largest prime no among the
list is "+a[i]);
break;
}
}
}
}
<----------------- It Works -------------------------->
| Is This Answer Correct ? | 9 Yes | 2 No |
Answer / rajani nagandla
1.Read n
2.lets take variables of type int (i=1,j=1,temp=0,count=0);
3. for (;i<n;i++){
count=0;
while(j<=i){
if((i%j)==0){
count+=1;
j++;
if(count>2)break;
}
}
if(count==2)
temp=i;
}
4.the value in temp after for loop execution will be the
Greatest Prime Number
| Is This Answer Correct ? | 6 Yes | 5 No |
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