Program to output as below formate:
1
2 3
4 5 6
7 8 9 10
Answers were Sorted based on User's Feedback
Answer / jyoti
public class format {
public static void main(String args[])
{
int k=1;
for(int i=0;i<5;i++)
{
for(int j=0;j<i;j++)
{
System.out.print(k++ + " ");
}
System.out.print("\n");
}
}
}
| Is This Answer Correct ? | 15 Yes | 3 No |
#include<stdio.h>
#include<conio.h>
void main()
{
int i=1,j,k;
clrscr();
for(j=0;j<4;j++)
{
for(k=0;k<=j;k++)
{
printf("%d "",i);
i++;
}
printf("\n");
}
getch();
}
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / debashree
In the above example one never knows how many lines are required to be print. So, to keep the program generic , we can implement it the following way:
public class FormattedOutput2 {
/**
* @param args
*/
public static void main(String[] args) {
printOutput(Integer.parseInt(args[0]), 1, 0);
}
private static void printOutput(int lastNum, int i, int num) {
int count = 0;
while(num < lastNum){
StringBuffer formatString = new StringBuffer();
while(count < i && num < lastNum){
formatString.append(++num + " ");
count++;
}
System.out.println(formatString);
i++;
count = 0;
}
}
}
Output for : 10
1
2 3
4 5 6
7 8 9 10
Output for: 102
1
2 3
4 5 6
7 8 9 10
11 12 13 14 15
16 17 18 19 20 21
22 23 24 25 26 27 28
29 30 31 32 33 34 35 36
37 38 39 40 41 42 43 44 45
46 47 48 49 50 51 52 53 54 55
56 57 58 59 60 61 62 63 64 65 66
67 68 69 70 71 72 73 74 75 76 77 78
79 80 81 82 83 84 85 86 87 88 89 90 91
92 93 94 95 96 97 98 99 100 101 102
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / dhananjaya nawarathne
public class formatNumbers {
public static void main(String args[])
{
int k=1;
for(int i=1;i<5;i++)
{
for(int j=0;j<i;j++)
{
System.out.print(k++ + " ");
}
System.out.print("
");
}
}
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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