I use turbo C which allocates 2 bytes for integers and 4
bytes for long. I tried to declare array of size 500000 of
long type using the following code...
long *arr;
arr=(long *)(malloc)(500000 * sizeof(long));
It gives a warning that "Conversion may lose significant
digits in function main"...
And the resulting array size was very less around 8400 as
compared to 500000. Any suggestions will be welcomed....
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Answer / anshu ranjan
I want to make a point here...I am not sure whether there is a limit to amount of memory that you can allocate using malloc...
I used this code in a program and it ran perfectly fine...
--------------
char **a;
int **val;
a =(char **) malloc ( 1000 * sizeof *a );
for ( i = 0; i < 1000; i++ )
a[i] =(char *) malloc ( 1000 * sizeof *a[i] );
val =(int **) malloc ( 1000 * sizeof *val );
for ( i = 0; i < 1000; i++ )
val[i] =(int *) malloc ( 1000 * sizeof *val[i] );
---------------
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / vignesh1988i
good morning to you.....
here what i suggest is that , at the time of dynamic memory allocation the memory would not been in the position to allocate that much of huge memory at a single instance...... UR MEMORY WILL BE INCAPABLE IF U TRY TO ALLOCATE A HUGE AMOUNT LIKE ABOVE FOR UR USE.......
u try this.... you declare an array size of 200 or 300... this will give a warning that MEMORY FULL........ the one of the disadvantages in C is that we cant balance a very large amount of data's which are outside the range .... so only we will go for DATA BASE.......
hope this helps u for getting some ideas.......
thank u
| Is This Answer Correct ? | 0 Yes | 0 No |
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