Answer / manish soni

manish soni tagore collage jaipur
ph:9785261817
e_mail:monupanhar@yahoo.comf;
hapy to help;

#include<iostream>
#include<stdio.h>
#include<conio.h>
using namespace std;
struct complex
{
int real;
int img;
};

void getdata(complex &);
complex sum(complex,complex);
complex mult(complex,complex);
void display(complex);

int main()
{
complex c1,c2,c3,c4;
getdata(c1);
getdata(c2);
c3=sum(c1,c2);
cout<<"Sum= ";
display(c3);
c4=mult(c1,c2);
cout<<"MULT= ";
display(c4);
getch();
return 0;
}
complex sum(complex c1,complex c2)
{
complex c;
c.real=c1.real+c2.real;
c.img=c1.img+c2.img;
return c;
}
void display(complex c)
{
cout<<c.real<<"+"<<c.img<<"i"<<endl;


}
complex mult(complex c1,complex c2)
{
complex c;
c.real=c1.real*c2.real-c1.img*c2.img;
c.img=c1.img*c2.real+c1.real*c2.img;
return c;
}
void getdata(complex &c)
{
cout<<"Enter first complex number:"<<endl;
cout<<"Enter real ";
cin>>c.real;
cout<<"Enter img ";
cin>>c.img;
}

Answer / a.bharathi raja bsc.,hdca.,

A.BHA RAJA
THENNAGALAPURI

#include<iostream.h>
#include<conio.h>
class complex
{
int r,i;
public:
{
void getdata(int a,int b)
{
r=a; i=b;
}
complex operator+(complex,complex);
void display(void);
};
complex complex :: operator+(complex a,complex b)
{
complex c;
c.r=a.r+b.r;
c.i=a.i+b.i;
return c;
}
void complex :: display(void)
{
cout<<r<<"+i"<<i<<"\n";
}
void main()
{
complex p,q,r;
int n,m;
clrscr();
cout<<"Enter the real number:";
cin>>n;
cout<<"Enter the imag number:";
cin>>m;
p.getdata(n,m);
cout<<"Enter the real number:";
cin>>n;
cout<<"Enter the imag number:";
cin>>m;
q.getdata(n,m);
r=p+q;
p.display(p);
q.display(q);
r.display(r);
getch();
}

Answer / sundari.b.v

#include<iostream.h>
#include<conio.h>
class complex
{
float x;
float y;
public:
complex(){}
complex(float real,float imag)
{
x=real;
y=imag;
}
complex operator+(complex);
void display(void);
};
complex complex::operator+(complex c)
{
complex temp;
temp x=x+c.x;
temp y=x+c.y;
return
}
void complex::display(void)
{
cout<<x<<"+j"<<y<<"\n";
}
int main()
{
complex c1,c2,c3;
c1=complex(2.5,3.5);
c2=complex(1.6,2.7);
c3=c1+c2;
cout<<"c1=",c1.display();
cout<<"c2=",c2.display();
cout<<"c3=",c3.display();
return 0;
}

Answer / a.bharathi raja

#include<iostream.h>
#include<conio.h>
class complex
{
int r;
int i;
public:
complex()
{ }
complex(int a,int b)
{
r=a;i=b;
}
friend complex operator+(complex,complex);
friend show(complex);
complex operator+(complex c1,complex c2)
{
complex c3;
c3.r=c1.r+c2.r;
c3.i=c1.i+c2.i;
return(c3);
}
show(complex c)
{
cout<<c.r<<"i+"<<c.i<<endl;
}
void main()
{
complex a,b,c;
clrscr();
a.complex(3,6);
b.complex(4,7);
c=a+b;
show(a);
show(b);
show(c);
getch()
}

Answer / arvind

write a c++ program to create class student having
datamember name,Roll_no,age,and branch intilcization all the
member using constructor print the all the details on the
screen.

Answer / aalok

// Program for complex operation by using operator overloading.
#include<iostream.h>
#include<conio.h>
class complex
{
int r,i;
public:
complex()
{}
void accept();
void display();
friend complex operator +(complex ,complex );
friend complex operator -(complex ,complex );
friend complex operator *(complex ,complex );
//friend complex operator /(complex ,complex );
}; // end of class complex.

void complex::accept()
{
cout<<"\n\n Enter Real & Imaginary part of complex";
cin>>r>>i;
} //end of accept().

void complex::display()
{
cout<<r<<"+"<<i<<"i";
} //end of display().


complex operator +(complex c1,complex c2)
{
complex ans;
ans.r=c1.r+c2.r;
ans.i=c1.i+c2.i;
return(ans);
} //end of complex +()

complex operator -(complex c1,complex c2)
{
complex ans;
ans.r=c1.r-c2.r;
ans.i=c1.i-c2.i;
return(ans);
} //end of complex -()

complex operator *(complex c1,complex c2)
{
complex ans;
ans.r=(c1.r*c2.r)-(c1.i*c2.i);
ans.i=(c1.r*c2.i)+(c1.i*c2.r);
return(ans);
} //end of complex *()

/*complex operator /(complex c1,complex c2)
{
complex ans,t1,t2;

t1.r=(c1.r*c2.r)+(c1.i*c2.i);
t1.i=(c1.i*c2.r)-(c1.r*c2.i);

t2.r=(c2.r*c2.r)+(c2.i*c2.i);
t2.i=0;

ans.r=t1.r/t2.r;
ans.i=t1.i/t2.i;
return(ans);
} //end of complex /() */


void main()
{
int ch;
complex c1,c2,c3;
clrscr();
cout<<"\n Enter first complex no";
c1.accept();
c1.display();
cout<<"\n Enter second complsx no";
c2.accept();
c2.display();

cout<<"\n\n~~~~~MENU~~~~~";
cout<<"\n 1. ADDATION ";
cout<<"\n 2. SUBTRACTION ";
cout<<"\n 3. MULTIPLACTION ";
cout<<"\n 4. DIVISION ";
cout<<"\n 5. EXIT ";
cout<<"\n\n Enter your choice = \t";
cin>>ch;

switch(ch)
{
case 1:
{
c3=c1+c2;
cout<<"\n ADDATION=";
c3.display();
} // end case 1.

case 2:
{
c3=c1-c2;
cout<<"\n SUBTRACTION=";
c3.display();
} // end case 2.

case 3:
{
c3=c1*c2;
cout<<"\n MULTIPLACTION=";
c3.display();
} // end case 3.

/* case 4:
{
c3=c1/c2;
cout<<"\n DIVISION=";
c3.display();
} // end case 4. */
} //end of switch case.

getch();
} //End of main ().

Answer / varsha

#include<iostream>
using namespace std;

class complex_number
{
int real_part;
int imaginary_part;
public:
void setData(int val,int flag)
{
real_part = 0;
imaginary_part = 0;
if(flag == 0)
{
real_part = val;
imaginary_part = 0;
}
else if(flag == 1)
{
real_part = 0;
imaginary_part = val;
}
}
void setData(int rp, int ip, int flag)
{ real_part = 0;
imaginary_part = 0;
if(flag == -1)
{
real_part = rp;
imaginary_part = ip;
}
}
void show()
{ if(imaginary_part>=0)
cout<<"Complex Number
is: "<<real_part<<"+"<<imaginary_part<<"i"<<endl;
else
cout<<"Complex Number
is: "<<real_part<<imaginary_part<<"i"<<endl;
}
complex_number operator+ (complex_number op2);
complex_number operator- (complex_number op2);
complex_number operator++();
complex_number operator++(int x);
};

complex_number complex_number:: operator+(complex_number
op2)
{
complex_number temp;
temp.real_part = op2.real_part + real_part;
temp.imaginary_part = op2.imaginary_part +
imaginary_part;
return temp;
}

complex_number complex_number:: operator-(complex_number
op2)
{
complex_number temp;
temp.real_part = real_part - op2.real_part;
temp.imaginary_part = imaginary_part -
op2.imaginary_part;
return temp;
}

complex_number complex_number:: operator++()
{
real_part++;
imaginary_part++;
return *this;
}
complex_number complex_number:: operator++(int x)
{
++real_part;
++imaginary_part;
return *this;
}
int main()
{
complex_number ob1;
ob1.setData(5,0);

complex_number ob2;
ob2.setData(10,1);
//cout<<"Before addition"<<ob2.show();
complex_number ob3;
ob3.setData(2,3,-1);
complex_number ob4;
ob4.setData(4,5,-1);
complex_number ob5;
cout<<"Before addition, complex numbers are :"<<endl;
ob4.show();
ob3.show();
ob5 = ob4+ob3;
cout<<"After Addition";
ob5.show();
cout<<"Before addition, complex numbers are :"<<endl;
ob1.show();
ob4.show();
ob5 = ob1 + ob4;
cout<<"After Addition";
ob5.show();
cout<<"Before addition, complex numbers are :"<<endl;
ob2.show();
ob4.show();
ob5 = ob2+ ob4;
cout<<"After Addition";
ob5.show();
cout<<"Before preincrement"<<endl;
ob5.show();
++ob5;
cout<<"After preincrement"<<endl;
ob5.show();
cout<<"Before postincrement"<<endl;
ob5.show();
ob5++;
cout<<"After postincrement"<<endl;
ob5.show();
cout<<"Before Subtraction, complex numbers are :"<<endl;
ob4.show();
ob3.show();
ob5 = ob4-ob3;
cout<<"After Subtraction";
ob5.show();
cout<<"Before Subtraction, complex numbers are :"<<endl;
ob1.show();
ob4.show();
ob5 = ob1 - ob4;
cout<<"After Subtraction";
ob5.show();
cout<<"Before Subtraction, complex numbers are :"<<endl;
ob2.show();
ob4.show();
ob5 = ob2- ob4;
cout<<"After subtraction";
ob5.show();


int i;
cin>>i;
return 0;
}

Answer / binoy

Write a C++ program to create a class called COMPLEX and
implement the following overloading functions ADD that
return a COMPLEX number .
I. ADD(a,s2) - where a is an integer(real part) and s2 is a
complex number.
II. ADD(s1,s2) - where s1 and s2 are complex objects.


#include<iostream.h>
#include<conio.h>
class complex
{
int r,i;
public:
void read();
void print();
friend complex add(int a,complex c);
friend complex add(complex c1,complex c2);
};
void complex::read()
{
cout<<"Enter real and imaginary\n";
cin>>r>>i;
}
void complex::print()
{
cout<<r<<"+i"<<i<<endl;
}
complex add(int a,complex c)
{
complex t;
t.r=a+c.r;
t.i=c.i;
return t;
}
complex add(complex c1,complex c2)
{
complex t;
t.r=c1.r+c2.r;
t.i=c1.i+c2.i;
return t;

}
void main()
{
int a=2;
clrscr();
complex s1,s2,s3;
s1.read();
cout<<"\ns1 : ";
s1.print();
s2=add(a,s1);
cout<<"s2 : 2+s1\n";
cout<<" : ";
s2.print();
s3=add(s1,s2);
cout<<"s3=s1+s2\n";
cout<<"s1 : ";
s1.print();
cout<<"s2 : ";
s2.print();
cout<<"s3 : ";
s3.print();
getch();
}


MORE C++ PROGRAMS AND SOLUTIONS:
1. ADDING 'TIME' OBJECTS AND DISPLAYING THE RESULT IN
HH:MM:SS FORMAT USING MEMBER FUNCTION

2. OPERATOR OVERLOADING - ADDITION, SUBTRACTION OF MATRICES
USING OPERATOR OVERLOADING

3. STACK IMPLEMENTATION USING OPERATOR OVERLOADING IN C++

http://programscpp.blogspot.in/

Answer / vishnu tiwari,cochin universit

It is a correct program,thanks a lot...........

Answer / waleed

i got a correct answer this will help me alot thanks

Find a five digit number subject to following conditions 1.It contains 2 prime no digits 2.3rd digit is the lagest. 3.1st digit = (3 rd digit - 1). 4.Sum of 4th digit and 5th digit is less than 1st digit. 5.Value of the 5th digit lies between the value of 1st digit and 2nd digit, 5th digit is one half of the 4th digit.

1 Answers  

unchanging velocity distribustion? heattransfer coffeicient?

0 Answers   HPCL,

hi cn nyone pls send me some model DRDO entrance exam's papers...my e-mail s tonysandeep_au@yahoo.co.in

0 Answers  

22. A solution of 1% (w/v) starch at pH 6.7 is digested by 15 &#956;g of &#946;&#8208;amylase (mol wt 152,000). The rate of maltose (mol wt = 342) had a maximal initial velocity of 8.5 mg formed per min. The turnover number is

0 Answers   CSIR,

4. Human code is a 1) error correcting code 2) lossless source code 3) lossy source code 4) error detecting code

1 Answers   PGEE,

voltage ratings of HT and LT power cables

0 Answers  

I am looking for bank exam coaching in Hyderabad. Can anybody tell me which is the best institute for BANK and which branch is good giving me branch details.

0 Answers  

c program to compare the initial portions of the two strings and return the matched portion if matches, otherwise return the empty string.

0 Answers  

please i need nautical science past question and answer

0 Answers  

When a overhead line is going in a jungle,How can we know in which side it comes and which side it goes.

0 Answers  

what is the name of transformer

2 Answers  

What is the broadcast address of the subnet address 172.16.8.159 255.255.255.192

2 Answers