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what is unreachable code problem in multiple catch statements
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Answer / deepthi
if v just gve a default exception block,bfre the specific
catch statement it ll create a unreachable code exception
e.g
catch(Exception e)
{System.out.println(unknown exception);}
catch(ArithmeticException e)
{System.out.println("Division by zero");}
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / sriragv
Subclass exception handler should come first then the
superclass has to come next. Then only code wil compile
otherwise subclass exception will be never reached results
compilation error.
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / bijoy baby
super class can handle sub class Exception. That's why when
super class handler placed before sub class handler then the
exception object will not thrown to sub class handler.
| Is This Answer Correct ? | 1 Yes | 0 No |
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