print first nodd numbers in descending order
Answers were Sorted based on User's Feedback
Answer / nagarajan n.
int n;
cout<<"enter a num:";
cin>>n;
for(int i=n;i>=1;i--)
{
if((i%2)!=0)
{
cout<<i<<"/t";
}
}
| Is This Answer Correct ? | 50 Yes | 26 No |
Answer / vaishnavi
#include<iostream.h>
void main()
{
int i,n;
cout<<"Enter the number:"
cin>>n;
for(i=2*(n-1);i>=1;i=i-2)
{
cout<<i;
}
}
| Is This Answer Correct ? | 8 Yes | 8 No |
Answer / dudelzy
#include <iostream>
using namespace std;
int main()
{
int num, x;
cout << "No. of odd numbers u want to find ";
cin >> num;
cout << "" << endl;
for(x = num; x <= num; x--){
if(x % 2 == 1){
cout << x << endl;
}
}
return 0;
}
| Is This Answer Correct ? | 0 Yes | 4 No |
Answer / prk
void main()
{
int i,n,k;
cout<<"Enter the number:";
cin>>n;
k=n%2;
if(k==0)
n=n-1;
for(i=n;i<=n;i=1-2)
cout<<1;
}
| Is This Answer Correct ? | 9 Yes | 15 No |
Answer / radhakrishnan
main()
{
int i,n,k;
cout>>"Enter the number:";
cin<<n;
k=n%2;
if(k==0)
n=n-1;
for(i=n;i<=n;i=1-2)
cout>>1;
}
| Is This Answer Correct ? | 3 Yes | 11 No |
Answer / rabid manatee
#include <iostream>
using namespace std;
int main(int argc, char *argv[]) {
int n = 4;
if (argc == 2) {
n = atoi(argv[1]);
}
for(int i=n; i >= 0; i--) {
cout << i*2 + 1 <<endl;
}
}
| Is This Answer Correct ? | 3 Yes | 14 No |
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