Answer / venkatesh sabinkar

#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
{
char ch[30],t,i1;
int i,j,max=1,n=1;
clrscr();
printf("enter the sentence\n");
gets(ch);
for(i=0;i<strlen(ch);i++)
{
for(j=i+1;j<strlen(ch);j++)
{
if(ch[i]>ch[j])
{
t=ch[i];
ch[i]=ch[j];
ch[j]=t;
}
}
}
printf("\n%s",ch);
for(i=0;i<strlen(ch);i++)
{
if(ch[i]==ch[i+1])
{
n+=1;
}
if( max<n)
{
max=n;
i1=ch[i];
}

}
printf("\n%c %d",i1,max);
getch();
}

Answer / vignesh1988i

add k++; in line 32.... sorry for mistake.



thank you

Answer / vignesh1988i

#include<stdio.h>
#include<conio. h>
void main()
{
char str[100],*ptr[50],a;
int count=0,count2=0,count,k=0;
printf("enter the string :");
fflush(stdin);
gets(str);
for(int i=0;str[i]!='\0';)
{
count=0;

if(str[i]==' ')
{
i++;
contine;
}
for(int j=i;str[j]!='\0';j++)
{
if(str[j]==' ')
continue;
if(str[i]==str[j])
count++;
}
if(count>count1)
{
count1=count;
a=str[i];
}
ptr[k]=&str[i];
i++;
count2++;
for(j=0;j<count2;j++)
{
if(str[i]==*(*(ptr+j)))
{
i++;
j=-1;
}
}
}
printf("the occurance of the char. is %c , count is %d times",a,count1);
getch();
}

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