write an interactive program to generate the divisors of a
given integer.
Answers were Sorted based on User's Feedback
Answer / neo
#include <stdio.h>
void div(int n){
int i=2;
while(n%i!=0 && i!=n){
i++;
}
printf("%d ",i);
if(i!=n){
div(n/i);
}
}
main(){
int i;
printf("Enter number:");scanf("%d",&i);
printf("1 ");
div(i);
}
| Is This Answer Correct ? | 25 Yes | 11 No |
Answer / rakesh ranjan
#include<conio.h>
#include<stdio.h>
main()
{
int n,i;
printf("entre the number");
scanf("%d",&n);
for(i=2;i<n;i++)
{
if(n%i==0)
printf("%d\n",i);
}
getch();
}
| Is This Answer Correct ? | 15 Yes | 2 No |
Answer / dally
#include<stdio.h>
int main()
{
int n,i=1;
printf("Value for n\n");
scanf("%d\n",&n);
while(i<=n)
{
if(n%i == 0)
printf("%d\n",i);
i++;
}
}
| Is This Answer Correct ? | 8 Yes | 5 No |
Answer / tamil
void div(int n){
static int i=1;
while(i<=n){
if(!(n%i))printf(" %d",i);
i++;
}
}
main(){
int i;
clrscr();
printf("Enter number:");scanf("%d",&i);
div(i);
getch();
}
| Is This Answer Correct ? | 11 Yes | 9 No |
Answer / guest
Optimised!! :-) some extra condition added to avoid printing repeated numbers.
#include<stdio.h>
void dev(int n,int i)
{
if(n <= i) return;
while(i <= n){
if((n % i) == 0){
if(n!=i) printf("%d ",i);
printf("%d ",n/i);
break;
}
i++;
}
dev(n/i,i+1);
return;
}
main()
{
int n;
printf("Enter number:");
scanf("%d",&n);
dev(n,2);
printf("\n");
return 0;
}
| Is This Answer Correct ? | 2 Yes | 5 No |
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