Answer / tulasi prasad

abstract class AbstractParent
{
void parentMethod1()
{
System.out.println("def of non abstract

method from parent");
}
abstract void parentMethod2();
}
abstract class AbstractChild extends

AbstractParent
{
void childMethod1()
{
System.out.println("def of non abstract

method from abstract child");
}
void parentMethod2()
{
System.out.println("def of parent abstract

method from abstract child");
}
abstract void childMethod2();
}
class ConcreteChild extends AbstractChild
{
void childMethod2()
{
System.out.println("def of child abstract

method from concrete child");
}
}
public class Test
{
public static void main(String args[])
{
ConcreteChild obj = new ConcreteChild();
obj.parentMethod1();
obj.parentMethod2();
obj.childMethod1();
obj.childMethod2();
}
}

Answer / puneet khanna

If you have 2 abstract classes say Abstract Class A and
Abstract Class b where B extends A;

B may not implement the abstract methods from A but the
class which will inherit B will have to give the
implementation of the abstract methods from class A and B both.

Answer / srinu

abstract class AbstractParent
{
void parentMethod1()
{
System.out.println("def of non abstract method from parent");
}
abstract void parentMethod2();
}

abstract class AbstractChild extends AbstractParent
{
void childMethod1()
{
System.out.println("def of non abstract method from
abstract child");
}
void parentMethod2()
{
System.out.println("def of parent abstract method from
abstract child");
}
abstract void childMethod2();
}
class ConcreteChild extends AbstractChild
{
void childMethod2()
{
System.out.println("def of child abstract method from
concrete child");
}
}
public class A1
{
public static void main(String args[])
{
ConcreteChild obj = new ConcreteChild();
obj.parentMethod1();def of non abstract method from parent
obj.parentMethod2();def of parent abstract method from
abstract child
obj.childMethod1();def of non abstract method from abstract
child
obj.childMethod2();def of child abstract method from
concrete child
}
}

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public class AboutStrings{ public static void main(String args[]){ String s1="hello"; String s2="hel"; String s3="lo"; String s4=s2+s3; //to know the hash codes of s1,s4. System.out.println(s1.hashCode()); System.out.println(s4.hashCode()); // these two s1 and s4 are having same hashcodes. if(s1==s4){ System.out.println("s1 and s4 are same."); }else System.out.println("s1 and s4 are not same."); } } Somebody told me that, == operator compares references of the objects. In the above example even though s1 and s4 are refering to same object(having same hash codes), it is printing s1 and s4 are not same. Can anybody explain in detail why it is behaving like this? Thanks in Advance RavuriVinod

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