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how can we design a magic square in c++?or suggest me the
basic idea of it.
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Answer / ganesh kundapur
Detail about the magic square
http://en.wikipedia.org/wiki/Magic_square.
To design a matrix sqaure, consider a 3X3 matrix.
n = 3;
* Fill the matrix with 0 or X. Start from the middle of the
first row ( i = 0, j = n/2)
+--+--+--+
|X_|1_|X_|
|X_|X_|X_|
|X_|X_|X_|
*. From 1, Go up rt corner(no row, and last column)(-1, 2),
and come down. and fill the next number at (2, 2)
X 1 X
X X X
X X 2
*. From 2, go right up corner( No column, 2nd row)(1, -1)
and if not any column, take a left and fill the next number
at (1, 0)
X 1 X
3 X X
X X 2
* From 3, go right up(0,1), It's already accupied, so come
down(2, 0) and fill the next number at (2,0)
X 1 X
3 X X
4 X 2.
* From node 4(2,0), up right up (1, 1), Its not accupied,
fill the next number at (1, 1)
X 1 X
3 5 X
4 X 2.
* From 5(1,1), Go right up(0,2) and its not accupied, fill
the next number at (0, 2)
X 1 6
3 5 X
4 X 2
* From x(0,2), go right up(No row, no column), so come down
from 6(1, 2), Its not accupied fill with the next number 7
at (1, 2)
X 1 6
3 5 7
4 X 2
* From 7(1, 2), Go up rt(1st row, no column), so take a left
and fill the unfilled node (0, 0)
8 1 6
3 5 7
4 X 2
* From 8(0,0), take up rt( No row, 1st column), come down
and fill the unfilled node at ( 2, 1)
8 1 6 sum = 15
3 5 7 sum = 15
4 9 2 sum = 15
sum 15 15 15
Diagonal sum = 15
Fallow the same procedure for 5X5, 7X7 square.
| Is This Answer Correct ? | 8 Yes | 3 No |
Answer / ganesh kundapur
void check(int *i,int *j,int n)
{
if(*i<0 && *j>=n) {
*i=*i+2;
*j=*j-1;
}
if(*i<=0 && *j<n)
*i=n-1;
if(*i>=0 && *j>=n)
*j=0;
}
/* n is the order of matrix 1, 3, 5... */
void DrawMagicTriangle(int n)
{
int **m;
int i, j, t, k = 0;
m=(int **)malloc(n*sizeof(int));
for(i=0; i<n; i++)
*(m+i)=(int *)malloc(n*sizeof(int));
for(i=0; i<n; i++)
for(j=0; j<n; j++)
m[i][j]=0;
i=0;
j=n/2;
for(t=0; t<n*n; t++) {
m[i][j]=++k;
i--;
j++;
if(i>=0 && j<n && m[i][j]!=0) {
i+=2;
j--;
}
else if(i>=0 && j<n && m[i][j]==0) {
i=i;
j=j;
}
else check(&i,&j,n);
}
for(i=0; i<n; i++) {
for(j=0; j<n; j++)
printf(" %d",m[i][j]);
printf("\n");
}
}
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / anu
I don't understand above answer.... can anyone explain in
detail...?? plz.....
| Is This Answer Correct ? | 0 Yes | 2 No |
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