Answer / madhu

We can't give both super() and this()in a constructor,
because both of these statements must be the first
statements in constructor. if you give super() as the first
statement then compiler error will come with this() call.
and vice versa.
but you can call the members with both super and this in a
constructor. here is the code.
class Base
{
Base()
{
System.out.println("Base constructor");
}
void m1()
{
System.out.println("m1 of Base");
}
}
class Derived extends Base
{
Derived()
{
super();//it is ok.
this();//raises compiler error
//but we can call the members with super and this
super().m1();//make sure that super()in
line must be marked comment
this().m1();
System.out.println("Derived constructor");
}
void m1()
{
System.out.println("m1 of Derived");
}
public static void main(String[] args)
{
Derived d=new Derived();
}
}
it works out

Answer / srikant bhat

it wil giv an exception -compiler exception

Answer / agile being

The question clearly specifies "what happen if u _CALL_
super and this in the same class"

By call, probably, they mean:
this(); /*Invoking the constructor*/
super(); /*Invoking the parent class's constructor*/

I think the right answer is that it will raise a compiler
exception. Such a program will not compile.

Answer / srikant bhat

wont there be any stack overflow?

Answer / srisanjana

No it doesn't work I have just tested

Answer / george

super and this will use first line of constructor so we cant
use it...i ll show error

Answer / raja

It Works fine with out any Exceptions,because in java each
and every class is inherited from the object class indirectly...

public class consex
{
public consex(String a)
{
super();

System.out.println(a);
}
public static void main(String dd[])
{

consex c=new consex("raja");

}
}

Answer / jyotshna pardhia

In a constructor if we call super and this in
the same class than we will get compile time error saying
that call to this() must be the first statement of the
construtor OR call to super() must be the first statement
of the constructor.So it is not possible to call
both in the same one.

Ex:-1
class Test
{
Test()
{
super();
this();
systm.out.println("hello Jyotshna");
}
}
error:- call to this() must be the first statement of
constructor.

Ex:-2
class Test
{
Test()
{
this();
super();
systm.out.println("hello Jyotshna");
}
}
error:- call to super() must be the first statement of
constructor.


Thanks & Regards
jyotshna

Answer / atul

class A
{
public A()
{ super();//this is perfect no error
super();//but this call generate RunTimeException
//because inside constructor super called
//must be in first called ok thats it
}
public static void main(String args[])
{
A a1=new A();

}
}

Answer / ajay dhingra

It will run fine with no exception here is the example :

public class CheckException extends Thread{
public CheckException(){
super.start();
this.start();
}
@Override
public synchronized void start() {
// TODO Auto-generated method stub
super.start();
}
}

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