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Write a Pseudo Code to find the angle between two hands of a
clock for a given time.
- 6 Answers
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Answer / batchu
#include<stdio.h>
#include<math.h>
#include<stdlib.h>
int main()
{
int hour,minute;
float angle;
printf("Enter the hour: ");
scanf("%d", &hour);
printf("Enter the minute: ");
scanf("%d", &minute);
if(hour>12)
{
hour = hour-12;
}
angle = hour * 30 + minute*0.5 - minute * 6;
if(angle>180)
{
angle = 360 - angle;
}
if (angle < 0 )
{
angle = angle * (-1);
}
printf("%f \n", angle);
return 0;
}
| Is This Answer Correct ? | 7 Yes | 2 No |
Answer / spacious mamun
#include<stdio.h>
int main()
{
int angle,hour,minute;
printf("Enter the hour: ");
scanf("%d", &hour);
printf("Enter the minute: ");
scanf("%d", &minute);
if(hour < 12) // In case of 24 hour clock
hour=hour+12;//to make the hour in 24 hour format;
{
(int)angle = hour * 30 - minute * 6;
if(angle > 180)
angle = 360 - angle;
printf("The angle between the two handle is: ");
printf("%d\n", angle);
}
return 0;
}
| Is This Answer Correct ? | 12 Yes | 11 No |
Answer / samer el-haj-mahmoud
#include<stdio.h>
int main()
{
int angle,hour,minute;
printf("Enter the hour: ");
scanf("%d", &hour);
printf("Enter the minute: ");
scanf("%d", &minute);
if(hour > 12) // In case of 24 hour clock
{
(int)angle = hour * 30 + minute / 2 - minute * 6;
if(angle > 180)
angle = 360 - angle;
printf("%d\n", angle);
}
else
printf("bye\n");
return 0;
}
| Is This Answer Correct ? | 6 Yes | 6 No |
Answer / thsghdth
le angle;
printf("Enter hour and minute in 24 hr format\n");
scanf("%d %d",&hr,&min);
angle=30*hr+(double)min/2-min*6;
if(angle<0) angle*=-1;
while(angle>180) angle-=180;
printf("%.2
| Is This Answer Correct ? | 2 Yes | 3 No |
Answer / fanatic
#include<stdio.h>
main()
{
int hr,min;
double angle;
printf("Enter hour and minute in 24 hr format\n");
scanf("%d %d",&hr,&min);
angle=30*hr+(double)min/2-min*6;
if(angle<0) angle*=-1;
while(angle>180) angle-=180;
printf("%.2f\n",angle);
return 0;
}
| Is This Answer Correct ? | 3 Yes | 6 No |
Answer / mamun
#include<stdio.h>
int main()
{
int angle,hour,minute;
printf("Enter the hour: ");
scanf("%d", &hour);
printf("Enter the minute: ");
scanf("%d", &minute);
if(hour > 12) // In case of 24 hour clock
{
(int)angle = hour * 30 - minute * 6;
if(angle > 180)
angle = 360 - angle;
printf("%d\n", angle);
}
else
printf("bye\n");
return 0;
}
| Is This Answer Correct ? | 2 Yes | 16 No |
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This is a puzzle question .... The warden meets with 23 new prisoners when they arrive. He tells them, "You may meet today and plan a strategy. But after today, you will be in isolated cells and will have no communication with one another. "In the prison is a switch room, which contains two light switches labeled A and B, each of which can be in either the 'on' or the 'off' position. I am not telling you their present positions. The switches are not connected to anything. "After today, from time to time whenever I feel so inclined, I will select one prisoner at random and escort him to the switch room. This prisoner will select one of the two switches and reverse its position. He must move one, but only one of the switches. He can't move both but he can't move none either. Then he'll be led back to his cell. "No one else will enter the switch room until I lead the next prisoner there, and he'll be instructed to do the same thing. I'm going to choose prisoners at random. I may choose the same guy three times in a row, or I may jump around and come back. "But, given enough time, everyone will eventually visit the switch room as many times as everyone else. At any time anyone of you may declare to me, 'We have all visited the switch room.' and be 100% sure. "If it is true, then you will all be set free. If it is false, and somebody has not yet visited the switch room, you will be fed to the alligators." What is the strategy they come up with so that they can be free?
C 
