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#include<stdio.h>
main()
{
char *p1;
char *p2;
p1=(char *) malloc(25);
p2=(char *) malloc(25);
strcpy(p1,"Ramco");
strcpy(p2,"Systems");
strcat(p1,p2);
printf("%s",p1);
}
Tell me the output?
- 6 Answers
- 16190 Views
- Ramco, I also Faced
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Answers were Sorted based on User's Feedback
Answer / sumant
the output will be RamcoSystems
but we need 2 more libraries
#include<string.h> and
#include<alloc.h>
to run this program. in else case it will not work.
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / mage
The program is not correct. What is present in memory
beyond "Ramco" is not known and we are trying to
attach "Systems". May be we are overwriting something which
is unsafe.
To concatenate two strings declare the first as array.
example: char p1[50];
char *p2;
p2 = malloc(25);
strcpy(p1, "Ramco");
strcpy(p2,"Systems");
strcat(p1,p2);
| Is This Answer Correct ? | 7 Yes | 1 No |
Answer / v.srinivasan
#include<stdio.h>
main()
{
char *p1,*p2;
p1 = (char *)malloc(25);
p2 = (char *)malloc(25);
strcpy(p1,"Ramco");
strcpy(p2,"Systems");
strcat(p1,p2);
printf("%s",p1);
}
the output will be RamcoSystems
we don't need the following libraries under Linux 2.6
#include<string.h> and
#include<alloc.h>
to run this program.
| Is This Answer Correct ? | 5 Yes | 0 No |
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