a=0;
while(a<5)
printf("%d\n",a++);
how many times does the loop occurs?
a.infinite
b.5
c.4
d.6
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Answer / bharath kumar
Hello,
The answer is b.
a=0+1=1
a=1+1=2
a=2+1=3
a=3+1=4
a=4+1=5
While a variable is storing the 5 result a is nither less
then are equal to 5 hence the application will come out of
the loop.So while loop had run 5 times.
| Is This Answer Correct ? | 28 Yes | 4 No |
Answer / vikram
the output will be:
0
1
2
3
4
hence the loop will be executed 5 times,hence the answer is b
| Is This Answer Correct ? | 17 Yes | 2 No |
Answer / deepu_ashu
as the value of "a" increases after printing the value.
so it will print the value
0
1
2
3
4
but after printing the value 4 ,it becomes 5 for the next iteration.
so the condition becomes false.
the loop will not execute any more.
| Is This Answer Correct ? | 12 Yes | 1 No |
Answer / vignesh1988i
THIS LOOP OCCURS 5 TIMES. AT THE SIXTH TIME IT BECOMES FALSE
| Is This Answer Correct ? | 12 Yes | 2 No |
Answer / ankit rastogi
ans should be (a)infinite
bcoz every time a will be initialize with 0......
and increment values are displayed
a=1
a=2
a=3
a=4...................upto infinity......
| Is This Answer Correct ? | 4 Yes | 3 No |
main() { int x=20,y=35; x = y++ + x++; y = ++y + ++x; printf("%d %d\n",x,y); }
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