write a c programs to do multiplication of two numbers with
out using arithmatic operator ??????????
Answers were Sorted based on User's Feedback
Answer / mugdha
#include<stdio.h>
#include<conio.h>
void main()
{int i, j ,num1,num2;
printf("enter the value of num1 & num2");
scanf("%d%d",&num1,&num2);
for(i=1; i<=num1; i++)
for(j=1;j<=num2;j++)
{static int k=1;
k++;
)printf("%d\n",k);}
| Is This Answer Correct ? | 12 Yes | 19 No |
Answer / mohan0877
#include<stdio.h>
main()
{
int a,b,result;
print("Enter values of a and b :")
scanf{"%d %d",&a,&b};
result=0;
while(b!=0)
{
if(b&01)
resultresul+a;
a<<=1;
b>>=1;
}
}
| Is This Answer Correct ? | 3 Yes | 13 No |
Answer / vivekananda
#include<stdio.h>
void main()
{
int num = 2;
res = num << 1; //multiplication by 2
printf("%d\n",res);
}
| Is This Answer Correct ? | 24 Yes | 37 No |
Answer / surajit
#include<stdio.h>
#include<conio.h>
void main()
{
int m,n,result=0;
printf("enter the value of m & n");
scanf("%d%d",&m,&n);
for(int i=1;i<=n;i++)
result=result+m;
printf("\n%d * %d =%d",m,n,result);
getch();
}
| Is This Answer Correct ? | 6 Yes | 19 No |
Answer / dally
#include<stdio.h>
int main()
{
int a=9,b=7;
int sum =0;
while(a--)
sum = sum+b;
printf("%d\n",sum);
}
| Is This Answer Correct ? | 12 Yes | 32 No |
Answer / vignesh1988i
#include<stdio.h>
#include<conio.h>
void main()
{
int m,n,result=0;
printf("enter the value of m & n");
scanf("%d%d",&m,&n);
for(int i=1;i<=n;i++)
result=result+m;
printf("\n%d * %d =%d",m,n,result);
getch();
}
| Is This Answer Correct ? | 34 Yes | 59 No |
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