Evaluate the following:
int fn(int v)
{
if(v==1 || v==0)
return 1;
if(v%2==0)
return fn(v/2)+2;
else
return fn(v-1)+3;
}
for fn(7);
1) 10
2) 11
3) 1
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the answer is : 11
solution :
since v=7
initially f(6)+ 3 is executed ( being a recurrsive
function) fn is again called with v=6 and the return now
is f(3) + 2 and again fn is called with v=3 and the return
now is f(2) +3 and again fn is called with v=0.now
recurrsion ends since f(0) is 1
f(0)=1
f(0)+2=3
f(2)=f(0)+2=1+2
f(2)+3=6
f(3)=f(2)+3=6
f(3)+2=6+2=8
f(6)=f(3)+2=8
f(6)+3=8+3=11
f(7)=f(6)+3
f(7)=11
now v hav to back track and keep adding
1+2+3+2+3 = 11.
| Is This Answer Correct ? | 14 Yes | 1 No |
Answer / abdur rab
The answer is 11
( 7 - 1 ) + 3 -> 11 = (8 +3)
( 6 / 2 ) + 2 --> 8 = (6 +2)
( 3 - 1 ) + 3 ---> 6 = (3 +3)
( 2 / 2 ) + 2 ----> 3 = (1 +2)
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / vinay
11 because it resrve every value in stack untill it become
1 then add all values.
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / chandrakala
this program returns the result as
1.
because,
7 is not equal to 1 or 0 and it is not mod by 2. so it will
go to else condition .in that 7-1 is performed and it mod
by 2 so 6/2=3 it once again go to else 3-1=2 is enter in to
function 2%2\=0 so 2/2 is performed.now v is 1 so it
returns 1 as answer.
| Is This Answer Correct ? | 5 Yes | 8 No |
Answer / lakshmi
first it checkes the main function i.e., fn()
int fn(7)
if(7==1||v==0) : this is false so the complier executes
the next if condition
if(7%2==0) : This is false so it executes the else
instruction
return fn(6)+3; :here we are again calling the fn
function .So the loop executes till the 7 becomes 1
After this the first if condition is true so it rerurns 1
to the function fn(1)+3
so the answer is 1.
| Is This Answer Correct ? | 0 Yes | 7 No |
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