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In the following declaration of main, "int main(int argc,
char *argv[])", to what does argv[0] usually correspond?




1) The first argument passed into the program


2) The program name


3) You can't define main like that

Question Posted / viju

Answers were Sorted based on User's Feedback



In the following declaration of main, "int main(int argc, char *argv[])", to what does a..

Answer / sanish joseph

No guys the ans s 2
it prints d program name:
arguments counts only from 1 nd nt 4m 0

Is This Answer Correct ?    15 Yes 0 No

In the following declaration of main, "int main(int argc, char *argv[])", to what does a..

Answer / ram

The answer is the program name.

Is This Answer Correct ?    12 Yes 0 No

In the following declaration of main, "int main(int argc, char *argv[])", to what does a..

Answer / vadivel

If the value of argc is greater than 0, the array members
argv[0] through argv[argc-1] inclusive shall contain
pointers to strings, which will be the command line
arguments. argv[0] will contain the program name, argv[1]
the first command line arg, argv[1] the second and so on.
Finally, argv[argc] is guaranteed to the a NULL pointer,
which can be useful when looping through the array.

Is This Answer Correct ?    2 Yes 0 No

In the following declaration of main, "int main(int argc, char *argv[])", to what does a..

Answer / sumeet sharma

argv[o] the array of strings will point to the name of the
program.
argv[1] will point to the first argument and so on.

Is This Answer Correct ?    1 Yes 0 No

In the following declaration of main, "int main(int argc, char *argv[])", to what does a..

Answer / zubeir

the answer is 1st choice.

Is This Answer Correct ?    8 Yes 8 No

In the following declaration of main, "int main(int argc, char *argv[])", to what does a..

Answer / mahi

my ans is 2.it prints the program name

Is This Answer Correct ?    0 Yes 0 No

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