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I have a function which accepts a pointer to an int. How
can I pass a constant like 5 to it?
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u have to take a temporary variable and pass its adress to
the pointer...like that given below:
// assuming all the conditions are given
int temp=5;
function(&temp);
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / jaya prakash
Only Using type modifiers only constant 5 is sent to
function.
[In previous 2 answers address of variable temp (5) is only
send to fn , not a constant 5]
for that fn-call is
function((int*)5);
| Is This Answer Correct ? | 0 Yes | 2 No |
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