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Can inline functions have a recursion? Give the reason?
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Answer / guest
Calling the by itself, then the function is no longer
called as Inline. Compiler never know how depth of the
recursion at compilation time. Therefore inline functions
cant have a recursion
| Is This Answer Correct ? | 14 Yes | 2 No |
Answer / sandeep mannarakkal
Inline is a request to the compiler , i.e it may get rejected for the following reasons,
1) If there is recursion (recursion have stack over stack, but inline don't have stack)
2) If static variable is available inside inline function
3) if function definition and implementation are available at different files
4) If there is a function pointer to inline function
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / siva
I have tested The answer is....
Yes, you can use but Not preferable.
Inline functions are expanded as macros at compile time.
Generally inline is used if the function has fewer lines of
code.
| Is This Answer Correct ? | 6 Yes | 9 No |
template<class T, class X> class Obj { T my_t; X my_x; public: Obj(T t, X x) : my_t(t), my_x(x) { } }; Referring to the sample code above, which one of the following is a valid conversion operator for the type T? a) T operator T () { return my_t; } b) T operator(T) const { return my_t; } c) operator(T) { return my_t; } d) T operator T (const Obj &obj) { return obj.my_t; } e) operator T () const { return my_t; }
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