byte a=5;
byte b=5;
byte c=a+b;
System.out.println(c);
whats the o/p?
Answers were Sorted based on User's Feedback
Answer / ravi
It will show compile time error
possible loss of precision
found int
reqired byte
| Is This Answer Correct ? | 27 Yes | 1 No |
Answer / amulkumar
CE:Type mismatch: cannot convert from int to byte
at byte c=a+b;
to avoid this typecast: byte c=(byte)a+b;
or
int c=a+b;
| Is This Answer Correct ? | 18 Yes | 6 No |
Answer / ravikiran
compilation fails
possibl;e loss of precision
because results in an int
| Is This Answer Correct ? | 10 Yes | 0 No |
Answer / janardhan
Above code , there is compile time error will coming, because
ie type mismatch error from byte to int, instead of byte we
can replace int(before a+b), it will excuite succesfully
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / kalyan
it will shows complie time error,to execute we typecast the
int to byte
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / dinesh kumar
compilation fails
possibl;e loss of precision, because
ie type mismatch error from byte to int, instead of byte we
can replace int(before a+b), it will excuite succesfully
| Is This Answer Correct ? | 1 Yes | 0 No |
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