without using arthematic operation ,how can you write the logic for adding/sub

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without using arthematic operation ,how can you write the
logic for adding/substraction/multiplication?

Question Posted / upendra

7 Answers
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without using arthematic operation ,how can you write the logic for adding/substraction/multiplica..

Answer / sumalatha

By using bitwise operators, we can implement addition,
subtraction and multiplication operations.

Is This Answer Correct ?

6 Yes

1 No

without using arthematic operation ,how can you write the logic for adding/substraction/multiplica..

Answer / madhusmita pal

using logical operator AND(^)OR(||)and XOR(-).

Is This Answer Correct ?

7 Yes

3 No

without using arthematic operation ,how can you write the logic for adding/substraction/multiplica..

Answer / sankar

Without using arthematic operation adding two numbers:

#include<stdio.h>
int main()
{
int a=5,b=6;
while(b)
{
a=a^b;
b=(a^b)&b;
b=b<<1;
}
printf("The sum of a and b is: %d\n",a);
return 0;
}

Is This Answer Correct ?

1 Yes

0 No

without using arthematic operation ,how can you write the logic for adding/substraction/multiplica..

Answer / xxx

ok without using arthematic operation? give a google search.
am also searching for that.

Is This Answer Correct ?

1 Yes

1 No

without using arthematic operation ,how can you write the logic for adding/substraction/multiplica..

Answer / upendra

plz send the answer for this quary

Is This Answer Correct ?

0 Yes

1 No

without using arthematic operation ,how can you write the logic for adding/substraction/multiplica..

Answer / ashwinkumar

int a = 10;
int b = 5;
int sum = BigInteger.valueOf(a).add(BigInteger.valueOf(b)).intValue();
int sum1 = BigInteger.valueOf(a).subtract(BigInteger.valueOf(b)).intValue();
int sum2 = BigInteger.valueOf(a).multiply(BigInteger.valueOf(b)).intValue();

Is This Answer Correct ?

2 Yes

3 No

without using arthematic operation ,how can you write the logic for adding/substraction/multiplica..

Answer / raaaj

visit nataraz.blogspot.com for the answer.you will get a lot of tricky question in future

Is This Answer Correct ?

0 Yes

1 No

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