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main()
{
int i=1;
while (i<=5)
{
printf("%d",i);
if (i>2)
goto here;
i++;
}
}
fun()
{
here:
printf("PP");
}

Answers were Sorted based on User's Feedback



main() { int i=1; while (i<=5) { printf("%d",i); if (i&..

Answer / surenda pal singh chouhan

Compiler error: Undefined label 'here' in function main

Explanation:
Labels have functions scope, in other words The scope of
the labels is limited to functions . The label 'here' is
available in function fun() Hence it is not visible in
function main.

Is This Answer Correct ?    16 Yes 0 No

main() { int i=1; while (i<=5) { printf("%d",i); if (i&..

Answer / jaroosh

Exactly, to be able to move control flow to here, you would
have to make a long jump using not very common functions
(that do actually more than goto) : setjmp and longjmp
(please look up those functions in google or some C standard
library reference).

Is This Answer Correct ?    5 Yes 1 No

main() { int i=1; while (i<=5) { printf("%d",i); if (i&..

Answer / dinakaran gct

The program is error because of the "goto" statement can't
jump from one segment to another segment i.e not support for
long jump.

Is This Answer Correct ?    3 Yes 0 No

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