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Why n++ execute faster than n+1 ?
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The expression n++ requires a single machine instruction such as INR to carry out the increment operation whereas, n+1 requires more instructions to carry out this operation.
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The expression n++ requires a single machine instruction such as INR to carry out the increment operation whereas, n+1 requires more instructions to carry out this operation.
| Is This Answer Correct ? | 0 Yes | 0 No |
main() { int i = -3,j=2,k=0,m; m= ++i || ++j && ++k; printf("%d%d%d",i,j,k,m); }
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#include<stdio.h> int f(int,int); int main() { printf("%d",f(20,1)); return 0; } int f(int n,int k) { if(n==0) return 0; else if(n%2)return f(n/2,2*k)+k; else return f(n/2,2*k)-k; } how this program is working and generating output as 9....?
Program will then find the largest of three numbers using nested if-else statements. User is prompted to enter three numbers. Program will find the largest number and display it on the screen. All three numbers entered by the user are also displayed. If user enters 21, 33, and 5, the output should be as follows: You entered: 21, 33 and 5. The largest number is 33.
C 
