public class AboutStrings{ public static void main(String args[]){ String s1="hello"; String s2="hel"; String s3="lo"; String s4=s2+s3; //to know the hash codes of s1,s4. System.out.println(s1.hashCode()); System.out.println(s4.hashCode()); // these two s1 and s4 are having same hashcodes. if(s1==s4){ System.out.println("s1 and s4 are same."); }else System.out.println("s1 and s4 are not same."); } } Somebody told me that, == operator compares references of the objects. In the above example even though s1 and s4 are refering to same object(having same hash codes), it is printing s1 and s4 are not same. Can anybody explain in detail why it is behaving like this? Thanks in Advance RavuriVinod

4 Answers   TCS,

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0 Answers   CGI,

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Hi Every One I Have Small Doubt Please answer This???????????????????????????? I Want to use AbstractList class methods(java.util.AbstractList) My Program is import java.util.*; class DemoOne extends AbstractList { public static void main(String[] args) { AbstractList a=new DemoOne();//This One is Correct?? DemoOne a1=new DemoOne();//This One is Correct?? Both Are Not Working System.out.println("Hello World!"+a); System.out.println("Hello World!"+a1); } } Error IS: DemoOne.java:2: DemoOne is not abstract and does not override abstract method get(int) in java.util.AbstractList class DemoOne extends AbstractList AnyOne can Please Provide The Solution????????????????????????? Plzzzzzzz

3 Answers  

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