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What is a command line shell?


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More Shell Script Interview Questions

determine the output of the following command: echo ${new:-variable}

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There is a record with fields namely name,roll no.,salary,grade etc.Now,write a script to create a file with multiple records have same combination of fields but with unique roll numbers.The script should work for different names in the input file.

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How to write an Auto scripting for deleting old files using shell script and made a cron job to run on daily basis

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What are "c" and "b" permission fields of a file?

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what is info area how many types?

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How to replace following lines, catch (DAOException e) { objLogger.error(this.getClass () + "addUpdateIssues() " + e); throw new BOException(5122); } catch (BOException e) { objLogger.error(this.getClass () + "addUpdateIssues() " + e); throw e; } catch (Exception e) { objLogger.error(this.getClass () + "addUpdateIssues() " + e); throw new BOException(5122); } Needs to be changed in to, catch (DAOException e) { AppException.handleException (null, null, e, null, null, null, "BOException", this.getClass() + "addUpdateIssues() ", null, null, null, null, null, null, null, null, 5122); } catch (BOException e) { AppException.handleException (null, null, null, e, null, null, "BOException", this.getClass() + "addUpdateIssues() ", null, null, null, null, null, null, null, null, 0); } catch (Exception e) { AppException.handleException (null, null, null, null, null, e, "BOException", this.getClass() + "addUpdateIssues() ", null, null, null, null, null, null, null, null, 5122); }

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Shifting positional parameter in Linux fedora core ? Hi I have written following shell script for display value of positional. But in 11th and 12 field will display without shifting command. May I know is it advance of Linux of programming code error? #!/usr/bin/bash echo "Bellow is the out of ps command" echo "`ps`" echo "The passing Parameter i.e output of \$1,2... value is:==> $11 " echo "Total number of passed argument \$# is:==> $#" echo "Passed argument names (\$*) are:==>$*" echo "This script PID(\$$) is :=>$$" echo "The name of executing script(\$0) is :==>$0" echo "The Parent ID of this script(\$PPID) is:==>$PPID" And my input to this script is ./scriptname arg1 arg2 arg3 arg4 arg5 arg6 arg7 arg8 arg9 arg10 arg11 arg12 Output Is Bellow is the out of ps command PID TTY TIME CMD 2892 pts/0 00:00:00 bash 3172 pts/0 00:00:00 positional_para 3173 pts/0 00:00:00 ps The passing Parameter i.e output of $1,2... value is:==> arg11 Total number of passed argument $# is:==> 13 Passed argument names ($*) are:==>arg1 arg2 arg3 arg4 arg5 arg6 arg7 arg8 arg9 arg10 arg11 arg12 arg13 This script PID($$) is :=>3172 The name of executing script($0) is :==>./positional_parameter The Parent ID of this script($PPID) is:==>2892 After the ps output please see the next line I.e $11 value comes out without shifting the parameter. How is it give me my friends

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How do you read arguments in a shell program - $1, $2 ..?

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What is egrep?

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What is the use of "$?" Sign in shell script?

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What is bash used for?

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Is bash an operating system?

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