What is a command line shell?
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determine the output of the following command: echo ${new:-variable}
There is a record with fields namely name,roll no.,salary,grade etc.Now,write a script to create a file with multiple records have same combination of fields but with unique roll numbers.The script should work for different names in the input file.
How to write an Auto scripting for deleting old files using shell script and made a cron job to run on daily basis
What are "c" and "b" permission fields of a file?
what is info area how many types?
How to replace following lines, catch (DAOException e) { objLogger.error(this.getClass () + "addUpdateIssues() " + e); throw new BOException(5122); } catch (BOException e) { objLogger.error(this.getClass () + "addUpdateIssues() " + e); throw e; } catch (Exception e) { objLogger.error(this.getClass () + "addUpdateIssues() " + e); throw new BOException(5122); } Needs to be changed in to, catch (DAOException e) { AppException.handleException (null, null, e, null, null, null, "BOException", this.getClass() + "addUpdateIssues() ", null, null, null, null, null, null, null, null, 5122); } catch (BOException e) { AppException.handleException (null, null, null, e, null, null, "BOException", this.getClass() + "addUpdateIssues() ", null, null, null, null, null, null, null, null, 0); } catch (Exception e) { AppException.handleException (null, null, null, null, null, e, "BOException", this.getClass() + "addUpdateIssues() ", null, null, null, null, null, null, null, null, 5122); }
Shifting positional parameter in Linux fedora core ? Hi I have written following shell script for display value of positional. But in 11th and 12 field will display without shifting command. May I know is it advance of Linux of programming code error? #!/usr/bin/bash echo "Bellow is the out of ps command" echo "`ps`" echo "The passing Parameter i.e output of \$1,2... value is:==> $11 " echo "Total number of passed argument \$# is:==> $#" echo "Passed argument names (\$*) are:==>$*" echo "This script PID(\$$) is :=>$$" echo "The name of executing script(\$0) is :==>$0" echo "The Parent ID of this script(\$PPID) is:==>$PPID" And my input to this script is ./scriptname arg1 arg2 arg3 arg4 arg5 arg6 arg7 arg8 arg9 arg10 arg11 arg12 Output Is Bellow is the out of ps command PID TTY TIME CMD 2892 pts/0 00:00:00 bash 3172 pts/0 00:00:00 positional_para 3173 pts/0 00:00:00 ps The passing Parameter i.e output of $1,2... value is:==> arg11 Total number of passed argument $# is:==> 13 Passed argument names ($*) are:==>arg1 arg2 arg3 arg4 arg5 arg6 arg7 arg8 arg9 arg10 arg11 arg12 arg13 This script PID($$) is :=>3172 The name of executing script($0) is :==>./positional_parameter The Parent ID of this script($PPID) is:==>2892 After the ps output please see the next line I.e $11 value comes out without shifting the parameter. How is it give me my friends
How do you read arguments in a shell program - $1, $2 ..?
What is egrep?
What is the use of "$?" Sign in shell script?
What is bash used for?
Is bash an operating system?