solve this is my problem byte a=40,byte b=50 both add value is 90 this is with in range of byte... byte range is -128to 127.... why this pgm gives error like type mismatch.... package javapgms; public class byte1 { public static void main(String args[]) { byte a=40,b=50; byte c=a+b; System.out.println(c); } } note : dont use int k... a,b,c are in byte range... mind it..

2 Answers  

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What is identifier give example?

0 Answers  

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I am unable to find or learn about print command. I have a graphical program in core java in applet but i want to give print command but i have coding for that so if anyone know about this plz mail me on avdhesh_chauhan007@yahoo.co.in

0 Answers  

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can you use the two main method in same class?how?

4 Answers   DELL, Geosoft, SparkTG,

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What are the parts of a method?

0 Answers  

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What is the purpose of stub and skeleton?

0 Answers  

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What is the java project architecture?

0 Answers   IBM,

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Explain about the main() method in java?

0 Answers  

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What is the difference between int and integer in java?

0 Answers  

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Is it compulsory to have atleast one abstract method in abstract class?

10 Answers  

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Explain about automatic type conversion in java?

0 Answers  

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Can we access private data outside of the class directly in java programming language? Why There is no runtime checking in java, which leads to access the private data directly outside of a class?

5 Answers   Google,

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