what will be the output off the following program? #include<stdio.h> int main() { int a; a=015+0*71+5; printf("%d,a"); return0; }

9 Answers   HCL,

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An arrangement of information in memory in such a way that it can be easily accessed and processed by a programming language a) string b) data structure c) pointers d) array

0 Answers  

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Write a C++ program without using any loop (if, for, while etc) to print prime numbers from 1 to 100 and 100 to 1 (Do not use 200 print statements!!!)

2 Answers   Cap Gemini, HCL,

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You have given 2 array. You need to find whether they will create the same BST or not. For example: Array1:10 5 20 15 30 Array2:10 20 15 30 5 Result: True Array1:10 5 20 15 30 Array2:10 15 20 30 5 Result: False One Approach is Pretty Clear by creating BST O(nlogn) then checking two tree for identical O(N) overall O(nlogn) ..we need there exist O(N) Time & O(1) Space also without extra space .Algorithm ?? DevoCoder guest Posted 3 months ago # #define true 1 #define false 0 int check(int a1[],int a2[],int n1,int n2) { int i; //n1 size of array a1[] and n2 size of a2[] if(n1!=n2) return false; //n1 and n2 must be same for(i=0;i<n1-1;i++) { if( !( (a1[i]>a1[i+1]) && (a2[i]>a2[i+1]) ) ) return false; } return true;//assumed that each array doesn't contain duplicate elements in themshelves }

0 Answers   Facebook,

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How the C program can be compiled?

11 Answers   HP,

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marge linklist

0 Answers   HCL,

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how to count no of words,characters,lines in a paragraph.

0 Answers  

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write a program to swap two variables a=5 , b= 10 without using third variable

5 Answers  

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in multiple branching construct "default" case is a) optional b) compulsarily c) it is not include in this construct d) none of the above

0 Answers  

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What is the difference between functions abs() and fabs()?

0 Answers  

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Can i use Two or More Main Funtion in any C program.?

4 Answers  

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what is the purpose of the following code, and is there any problem with the code? void fn(long* p1, long* p2) { register int x = *p1; register int y = *p2; x ^= y; y ^= x; x ^= y; *p1 = x; *p2 = y; }

1 Answers   Google,

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