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Explain shallow copy?
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class A { public: void f(); protected: A() {} A(const A&){} }; Examine the class declaration shown above. Why are the default and copy constructors declared as protected? 1. To ensure that A cannot be created via new by a more derived class 2. To ensure that A cannot be copied 3. To ensure that A cannot be used as a base class except when public inheritance has been used 4. To ensure that A cannot be created/copied outside the inheritance chain 5. To ensure that A cannot be instantiated as a static variable
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