What is the problem of ordered sequential files access?
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The maximum number of dimensions that an array can have in COBOL-85 is ?
COMPUTE X = A * B - C * D and COMPUTE X = (A * B) - (C * D) (a) Are not the same (b) Are same (c) Syntactically wrong (d) Will yield a run time error
I have two files , file1 is input file it contains 10,20,30,....,records but i want to display the records in file 2 as reverse order .how can we do by using jcl& cobol(dont use array) please any one can tell me the answer
What kind of error is trapped by on size error option?
WE HAVE 2 FILES IN COBOL. ONE IS FIXED LENGTH RECORDS ANOTHER ONE IS VARIABLE LENGTH. IF I DECLEAR LRECL OF FIXED ONE AS 80 AND 2ND RECORD AS 132. WHAT WE NEED TO DECLEAR LRECL FOR THOSE 2 FILES IN JCL?
if we display var1 then what will b displayed in below condition. 77 var1 pic s9(2) value -10. 77 var1 pic s9(2) value -11. " " " -12. " " " -13. -14 ... ... -19.
what is Reentrancy and Quasi-reentrancy?
What is a SSRANGE and NOSSRANGE?
Explain what you understand by passing by value.
I have two questions here. 1. How to read a flat file in reverse order? 2. How to read a VSAM KSDS file in reverse order? In both the cases we donot know the total number of records.
what is the difference b/w level no.01 & level no.77?
given the following: 77 A PIC 9V9 VALUE 9.5 77 B PIC 9 VALUE 9. 77 C PIC V9 VALUE 0.8 77 D PIC 9 77 E PIC 9 77 F PIC 9V999 what are the contenta of D E nad F after the following statements are executed: COMPUTE F ROUNDED=A+C/B MULTIPLY A BY C GIVING E ADD B C A GIVING D ROUNDED a.F=9.589 E=8 D=1 b.F=9.589 E=8 D=9 c.F=9.589 E=7 D=9 d.F=9.589 E=7 D=1