interface X{ void m1(); void m2(); } class Child2 extends Object implements X { public void m1(){ System.out.println("Child2 M1"); } public void m2(){ System.out.println("Child2 M2"); } } public class ParentChildInfterfaceDemo { public static void main(String[] args){ X x = new Child2(); X x1 = new Child2(); x.m1(); x.m2(); x.equals(x1); } } Will the above code work? If yes? Can you please explain why the code x.equals(x1) will work as the equals method is called on interface reference vaiable?

2 Answers  

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public class AboutStrings{ public static void main(String args[]){ String s1="hello"; String s2="hel"; String s3="lo"; String s4=s2+s3; //to know the hash codes of s1,s4. System.out.println(s1.hashCode()); System.out.println(s4.hashCode()); // these two s1 and s4 are having same hashcodes. if(s1==s4){ System.out.println("s1 and s4 are same."); }else System.out.println("s1 and s4 are not same."); } } Somebody told me that, == operator compares references of the objects. In the above example even though s1 and s4 are refering to same object(having same hash codes), it is printing s1 and s4 are not same. Can anybody explain in detail why it is behaving like this? Thanks in Advance RavuriVinod

4 Answers   TCS,

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0 Answers  

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2 Answers   CMC,

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0 Answers  

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0 Answers   TCS,

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0 Answers  

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4 Answers   Ness Technologies,

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0 Answers  

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0 Answers  

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0 Answers  

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The class "Class" is belongs to which package?? a) java.lang b)java.lang.reflect c)java.util d)None

4 Answers  

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