Answer / vijaya

we can always fetch from one database and rewrite to
another. Here is a nice solution of it.

$db1 = mysql_connect(”host”,”user”,”pwd”)
mysql_select_db(”db1″, $db1);
$res1 = mysql_query(”query”,$db1);
$db2 = mysql_connect(”host”,”user”,”pwd”)
mysql_select_db(”db2″, $db2);
$res2 = mysql_query(”query”,$db2);At this point you can only
fetch records from you previous ResultSet,

i.e $res1 - But you cannot execute new query in $db1, even
if you supply the link as because the link was overwritten
by the new db.so at this point the following script will fail

$res3 = mysql_query(”query”,$db1); //this will failSo how to
solve that?

Take a look below.

$db1 = mysql_connect(”host”,”user”,”pwd”)
mysql_select_db(”db1″, $db1);
$res1 = mysql_query(”query”,$db1);

$db2 = mysql_connect(”host”,”user”,”pwd”, true)
mysql_select_db(”db2″, $db2);
$res2 = mysql_query(”query”,$db2);

So mysql_connect has another optional boolean parameter
which indicates whether a link will be created or not. as we
connect to the $db2 with this optional parameter set to
‘true’, so both link will remain live.

now the following query will execute successfully.
$res3 = mysql_query(”query”,$db1);

Answer / ravinder

by using import and export

equivalent code for the following c program in php void main() { int i=5;printf("%d",i); }

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