Answer / adeel

#include<iostream>

using namespace std;

int main()
{
int i,j;
for(i=0; i<=5; i++)
for(j=1; j<=i; j++)

cout<<j;

system("pause");
return 0;
}

why to use operator overloading

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any one please tell me the purpose of operator overloading

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1.explicit call for destructor 2.calling function inside a constructor. 3.base *b-new derived delete b; 4.delete p what it will delete. 5.size of base class and derived class int i,in base class and int j in derived. 6.int i-20 int main() { int i =5; printf("%d".::i); { int i =10; printf("%d".::i); } } 7.object slicing 8.new 9.function overloading(return type). 10.class base() { virtuval fun() { ----- } } class derivied:public base() { fun() { ----- } } int main() { derived d; } 11.how static function will call in C++? 12.default structures are in C++? 13.constructors should be in public . 14.virtuval constructor not exist. 15.multilevel inhritence. destructor order.

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