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#include<stdio.h>
int main(){
int a[]={1,2,3,5,1};
int *ptr=a+4;
int y=ptr-a;
printf("%d",y);
}

Question Posted / anunithi

Answers were Sorted based on User's Feedback



#include<stdio.h> int main(){ int a[]={1,2,3,5,1}; int *ptr=a+4; int y=ptr-a; printf(&q..

Answer / harsha

as per my knowledge..4
a is base address of array
every array is a pointer
difference between the pointers is count of data elements ,but not difference between address
y=a+4-a
i.e., y=4

Is This Answer Correct ?    5 Yes 0 No

#include<stdio.h> int main(){ int a[]={1,2,3,5,1}; int *ptr=a+4; int y=ptr-a; printf(&q..

Answer / anunithi

4

Is This Answer Correct ?    6 Yes 3 No

#include<stdio.h> int main(){ int a[]={1,2,3,5,1}; int *ptr=a+4; int y=ptr-a; printf(&q..

Answer / sridhar

1

Is This Answer Correct ?    0 Yes 1 No

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