How do we make a class serialize?
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We have to fallow below steps to serialize an object
1. The object to be serialized need to implement java.io.Serializable / java.io. Externalizable interface.
2. Generate serial version id for that serializable object.
3. ObjectOutputStream is used to write [writeObject(..) or wirteExternal()] object.
4. FileOutputStream is used to persist in flat file.
5. The flat file extension should be (<file-name>.ser)
| Is This Answer Correct ? | 3 Yes | 0 No |
We have to fallow below steps to serialize an object
1. The object to be serialized need to implement java.io.Serializable interface.
2. It will use Java’s default serialization mechanism.
3. Generate serial version id for that serializable object.
4. Only default constructor is applicable to all class hierarchy (from child to all super classes if any). It is necessary at deserialization otherwise throw InvalidClassException.
5. Generate serial version UID for all super classes in hierarchy (all super classes if any) otherwise the properties of all its super classes will be assigned to its default value during deserializtion.
6. ObjectOutputStream is used to write [writeObject] object.
7. FileOutputStream is used to persist in flat file.
8. The flat file extension should be (<file-name>.ser)
| Is This Answer Correct ? | 1 Yes | 0 No |
Here is the updated answer
We have to fallow below steps to serialize an object
1. The object to be serialized need to implement java.io.Serializable interface.
2. It will use Java’s default serialization mechanism.
3. Generate serial version id for that serializable object.
4. Generate serial version UID for all super classes in hierarchy (all super classes if any) otherwise the properties of all its super classes will be assigned to its default value during deserializtion.
5. ObjectOutputStream is used to write [writeObject] object.
6. FileOutputStream is used to persist in flat file.
7. The flat file extension should be (<file-name>.ser)
| Is This Answer Correct ? | 0 Yes | 0 No |
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