main() { int i; for(i=0;i<5;i++) printf("%d",1l<<i); }

main()
{
int i;
for(i=0;i<5;i++)
printf("%d",1l<<i);
}
why doesn't 'l' affect the code??????

Question Posted / addu

main() { int i; for(i=0;i<5;i++) printf("%d",1l<<i); } why doesn't �..

In 1l, 'l' converts number 1 from int to long int.
It is a valid expression

Is This Answer Correct ?

2 Yes

0 No

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