Answer / bhavya b

square of a no: n is the sum of first n odd no: for eg ..square of 7 is 1+3+5+7+9+11+13=49...
so we can find sqrt(m) by decrementing odd no:s from m upto m become 0 or less..then the no: of odd no:'s decremented will give the sqrt(m).

int sqroot(int m){
int n=0,i=1;
while(m>0){
m=m-i;
i+=2;
n++;
}
return(n);
}

Answer / akash dilwaria

#iclude<iostream.h>
#nclude<conio.h>
void main()
{
clrscr();
int n;
float sqrt;
cout<<"\n enter the number";
cin>>n;
sqrt=pow(n,0.5);
cout<<"\n square root of a number is="<<sqrt;
getch();
}

Answer / avinash

private int sqrt()
{
int n = console.readline();

n = n*n;

return n;
}

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