int n=1; while(1) { switch(n) { case 1:printf("a"); n++; contin

int n=1;
while(1)
{
switch(n)
{
case 1:printf("a");
n++;
continue;
case 2:printf("b");
n++;
continue;
default : printf("c");
break;
}
break;
}

Question Posted / shravan katta

int n=1; while(1) { switch(n) { case 1:printf("a"); n++; continue; case 2:printf(&..

Answer / arun

abc

Is This Answer Correct ?

3 Yes

1 No

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