why array index always starts from zero??
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It uses the concept of Binary digits. Take an array size of 64 for example. We start from 0 and end at 63,
We require 6 bits.But, if we were to start from 1 and end at 64, we would require 7 bits to store the same number,
thus increasing the storage size.
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / bijayalaxmi behera.
The index of an array is an OFFSET from the beginning of the
array, multiplied by the width of the array items:
Say an array of integers, 4 bytes long.
Say beginning of array at address 0x1000
First integer address: BaseAddress + (index * len) = 0x1000
+ ( 0 * 4) = 0x1000
Second integer will be at : 0x1000 + ( 1 * 4 ) = 0x1004.
| Is This Answer Correct ? | 4 Yes | 6 No |
Answer / nobody special
because starting from 3 would just be silly?
| Is This Answer Correct ? | 1 Yes | 9 No |
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