Answer / sorab

#define square(x) x*x
main()
{
int i;
i = 64/square(4);
printf("%d",i);
}
the macro call square(4) will substituted by 4*4 so the expression becomes i = 64/4*4 . Since / and * has equal priority the expression will be evaluated as (64/4)*4 i.e. 16*4 = 64

#include<stdio.h> int main() { int i=2; int j=++i + ++i + i++; printf("%d\n",i); printf("%d\n",j); }

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