Answer / sorab

#define square(x) x*x
main()
{
int i;
i = 64/square(4);
printf("%d",i);
}
the macro call square(4) will substituted by 4*4 so the expression becomes i = 64/4*4 . Since / and * has equal priority the expression will be evaluated as (64/4)*4 i.e. 16*4 = 64

what will the following program do? void main() { int i; char a[]="String"; char *p="New Sring"; char *Temp; Temp=a; a=malloc(strlen(p) + 1); strcpy(a,p); //Line no:9// p = malloc(strlen(Temp) + 1); strcpy(p,Temp); printf("(%s, %s)",a,p); free(p); free(a); } //Line no 15// a) Swap contents of p & a and print:(New string, string) b) Generate compilation error in line number 8 c) Generate compilation error in line number 5 d) Generate compilation error in line number 7 e) Generate compilation error in line number 1

1 Answers   IBM,

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what is out put of the following code? #include class Base { Base() { cout<<"constructor base"; } ~Base() { cout<<"destructor base"; } } class Derived:public Base { Derived() { cout<<"constructor derived"; } ~Derived() { cout<<"destructor derived"; } } void main() { Base *var=new Derived(); delete var; }

3 Answers   Honeywell,

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0 Answers  

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Study the following C program :call_me (myvar)int myvar;{ myvar +- 5; }main(){int myvar;myvar = 3;call_me(myvar);printf("%d ",myvar);What will be printed a) 3 b) 5 c) 8 d) symbol

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9 Answers  

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0 Answers  

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5 Answers   TCS,

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2 Answers  

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1 Answers   NIIT,

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0 Answers  

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why wipro wase

0 Answers   Wipro,

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