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how to add two numbers without using arithmetic operators?
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Answer / sanjay bhosale
int x=12382,y=2;
int xor, and, temp;
and = x & y;
xor = x ^ y;
while(and != 0 )
{
and <<= 1;
temp = xor ^ and;
and &= xor;
xor = temp;
}
printf(" sum is : %d",xor);
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / shashishekar
#include<stdio.h>
#include<conio.h>
int main()
{
int a= 10;
int b=5;
int sum=0;
sum= a-(~b)-1;
printf(" sum= %d",sum);
getch();
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / mallikarjun
#include<stdio.h>
#include<conio.h>
main()
{
int a= 10;
int b=5;
sum=0;
sum= a&&b;
printf(" sum= %d",sum);
}
| Is This Answer Correct ? | 9 Yes | 10 No |
Answer / rajkumar
#include<stdio.h>
#include<conio.h>
void main()
{
int a=6,b=3,sum=0;
sum=a^b;
printf("sum=%d",sum);
getch();
}
| Is This Answer Correct ? | 3 Yes | 9 No |
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