public class Base { public void myMethod(int a,intb) {} } // Uses myMet

public class Base {
public void myMethod(int a,intb) {}
}

// Uses myMethod and then hides it.
public class DerivedOne extends Base {

private void myMethod(int a,int b);
}

will this compile or not .yes or no. why

Question Posted / rrokkerr87

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public class Base { public void myMethod(int a,intb) {} } // Uses myMethod and then hides i..

Answer / ashwin khandelwal

It cannot be compiled because of weaker access privilege give to method in DerivedOne class while overidding method of Base Class

Is This Answer Correct ?

12 Yes

0 No

public class Base { public void myMethod(int a,intb) {} } // Uses myMethod and then hides i..

Answer / narayana

This will not compile because in the base class myMethod()
function is not having the body ,only abstract methods
should not have the body remaining all methods should have
the body

Is This Answer Correct ?

6 Yes

6 No

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