write a vb script to display apple that is 1st a should be
displayed then ap then app then appl then apple
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Answer / aparajita mohapatra
val="apple"
For i=1 to len(val)
val1=mid(val,1,i)
print val1
Next
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / usha
str="apple"
for i = 1 to len(str)
msgbox left(str,i)
next
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / mudaseer
above answer is almost correct but there is one mistake
val="apple"
For i=1 to len(val)
val1=mid(val,1,i)
msgbox val1
Next
instead of msgbox he has used print
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / prathyusha
str="apple"
For i=1 To Len(str)
var=Mid(str,i,1)
char=char&var
newchar=newchar&vbcrlf&char
Next
MsgBox newchar
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / abhishek mallabadi
dim apple
apple="a"
msgbox apple
apple1=apple & "p"
msgbox apple1
apple2=apple1 & "p"
msgbox apple2
apple3=apple2 & "l"
msgbox apple3
apple4=apple3 & "e"
msgbox apple4
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / sadashivbyagi
guys dont complex the simple qn's
just try for this k
msgbox "a"&" "&"ap"&" "&"app"&" "&"appl"&" "&"apple"
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / mudaseer
msgbox "a"
msgbox "ap"
msgbox "app"
msgbox "appl"
msgbox "apple"
| Is This Answer Correct ? | 0 Yes | 5 No |
what is diff b/n these 2 programs 1) for i=5 to 1 step 2 msgbox "pass" next 2_) for i=5 to 1 step -2 msgbox "pass" next
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