I have array like
$array = array(1, "hello", 1, "world", "hello");
if i want the following output then how can i do this?
Array
(
[1] => 2
[hello] => 2
[world] => 1
)

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I have array like $array = array(1, "hello", 1, "world", "hello"); i..

Answer / sreejesh1987

import java.io.*;
class Duply
{
public static void main(String args[])
{
int i,n;
String [] array=new String[20];
String []cp=new String[20];
int []f=new int[20];
DataInputStream ds=new DataInputStream(System.in);

try
{
System.out.println("Enter the number of elements:");
n=Integer.parseInt(ds.readLine());


System.out.println("Enter the elements");
for(i=0;i<n;i++)
{
array[i]=ds.readLine();
f[i]=1;
}

cp=array;

for(i=0;i<n;i++)
{
for(int j=0;j<i;j++)
if(array[i].equals(cp[j]))
{
f[i]++;
cp[j]=null;
}
}




for(i=0;i<n;i++)
if(cp[i]!=null)
System.out.print("array["+cp[i]+"]:"+f[i]+"\n");



}


catch(Exception e){}


System.exit(0);
}
}

Is This Answer Correct ?    1 Yes 1 No

I have array like $array = array(1, "hello", 1, "world", "hello"); i..

Answer / sreejesh1987

import java.io.*;
class Duply
{
public static void main(String args[])
{
int i,n;
String [] array=new String[20];
int []f=new int[20];
DataInputStream ds=new DataInputStream(System.in);

try
{
System.out.println("Enter the number of elements:");
n=Integer.parseInt(ds.readLine());

System.out.println("Enter the elements");
for(i=0;i<n;i++)
{
array[i]=ds.readLine();
f[i]=0;
}

for(i=0;i<n;i++)
{
for(int j=0;j<i;j++)
if(array[i].equals(array[j]))
{
f[j]++;
f[i]=-1;
}
if(f[i]==0) f[i]=1;
}
for(i=0;i<n;i++)
if(f[i]>0)
System.out.print("array["+array[i]+"]:"+f[i]+"\n");
}
catch(Exception e){}
System.exit(0);
}
}

Is This Answer Correct ?    0 Yes 0 No

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